openpyxl:chart.title =“图表标题”不起作用。如何将标题添加到散点图?

时间:2018-08-07 01:40:41

标签: openpyxl

我正在使用Python 3.6.3和openpyxl 2.5.4

我写了一些代码,发现用chart.title = "Test Heading"设置图表标题没有任何作用。作为健全性检查,我复制并运行了example from here

from openpyxl import Workbook
from openpyxl.chart import (
    ScatterChart,
    Reference,
    Series,
)

wb = Workbook()
ws = wb.active

rows = [
    ['Size', 'Batch 1', 'Batch 2'],
    [2, 40, 30],
    [3, 40, 25],
    [4, 50, 30],
    [5, 30, 25],
    [6, 25, 35],
    [7, 20, 40],
]

for row in rows:
    ws.append(row)

chart = ScatterChart()
chart.title = "Scatter Chart"
chart.style = 13
chart.x_axis.title = 'Size'
chart.y_axis.title = 'Percentage'

xvalues = Reference(ws, min_col=1, min_row=2, max_row=7)
for i in range(2, 4):
    values = Reference(ws, min_col=i, min_row=1, max_row=7)
    series = Series(values, xvalues, title_from_data=True)
    chart.series.append(series)

ws.add_chart(chart, "A10")

wb.save("scatter.xlsx")

可悲的是,示例输出中的标题仍然丢失: enter image description here

奇怪的是,将title_from_data=True更改为title_from_data=False似乎也对图表的内容没有影响。

1 个答案:

答案 0 :(得分:1)

这很像是您用来查看文件的应用程序中的错误,我怀疑是LibreOffice。