我正在使用Spring Boot REST,我想在序列化过程中更改JSON响应的结构。
我有以下型号:
Title.java
@Entity
public class Title {
private Short id;
private String name;
private Collection<TitleCelebrity> titleCelebrities;
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
@Column(name = "id")
public Short getId() {
return id;
}
public void setId(Short id) {
this.id = id;
}
@Basic
@Column(name = "name")
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
@OneToMany(mappedBy = "title")
public Collection<TitleCelebrity> getTitleCelebrities() {
return titleCelebrities;
}
public void setTitleCelebrities(Collection<TitleCelebrity> titleCelebrities) {
this.titleCelebrities = titleCelebrities;
}
}
TitleCelebrity.java
@Entity
@Table(name = "title_celebrity")
public class TitleCelebrity {
private TitleCelebrityPK id;
private String characterName;
private Title title;
private TitleCelebrityType titleCelebrityType;
@EmbeddedId
@JsonIgnore
public TitleCelebrityPK getId() {
return id;
}
public void setId(TitleCelebrityPK id) {
this.id = id;
}
@Basic
@Column(name = "character_name")
public String getCharacterName() {
return characterName;
}
public void setCharacterName(String characterName) {
this.characterName = characterName;
}
@MapsId("titleByTitleId")
@ManyToOne
@JoinColumn(name = "title_id", referencedColumnName = "id", nullable = false)
@JsonIgnore
public Title getTitle() {
return title;
}
public void setTitle(Title title) {
this.title = title;
}
@MapsId("titleCelebrityTypeByTitleCelebrityTypeId")
@ManyToOne
@JoinColumn(name = "title_celebrity_type_id", referencedColumnName = "id", nullable = false)
public TitleCelebrityType getTitleCelebrityType() {
return titleCelebrityType;
}
public void setTitleCelebrityType(TitleCelebrityType titleCelebrityType) {
this.titleCelebrityType = titleCelebrityType;
}
}
TitleCelebrityType.java
@Entity
@Immutable
@Table(name = "title_celebrity_type")
public class TitleCelebrityType {
private Short id;
private String name;
private Collection<TitleCelebrity> titleCelebrities;
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
@Column(name = "id")
public Short getId() {
return id;
}
public void setId(Short id) {
this.id = id;
}
@Basic
@Column(name = "name")
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
@OneToMany(mappedBy = "titleCelebrityType")
@JsonIgnore
public Collection<TitleCelebrity> getTitleCelebrities() {
return titleCelebrities;
}
public void setTitleCelebrities(Collection<TitleCelebrity> titleCelebrities) {
this.titleCelebrities = titleCelebrities;
}
}
因此,当我请求获取标题时,JSON响应如下所示:
{
"id": 1,
"name": "Vertigo",
"titleCelebrities": [
{
"characterName": "John 'Scot",
"titleCelebrityType": {
"id": 1,
"name": "Cast"
}
},
{
"characterName": "Madeleine ",
"titleCelebrityType": {
"id": 1,
"name": "Cast"
}
},
{
"characterName": "a",
"titleCelebrityType": {
"id": 2,
"name": "Director"
}
},
{
"characterName": "b",
"titleCelebrityType": {
"id": 3,
"name": "Writer"
}
},
{
"characterName": "c",
"titleCelebrityType": {
"id": 3,
"name": "Writer"
}
}
]
}
在没有更改POJO类(模型)的情况下是否存在?
{
"id": 1,
"name": "Vertigo",
"titleCelebrities": [
{
"cast": {
"characterName": "John 'Scot",
"characterName": "Madeleine ",
},
"director": {
"characterName": "a",
},
"writer": {
"characterName": "b",
"characterName": "c",
}
},
]
}
答案 0 :(得分:2)
您可以使用 DTO :
将数据封装在可以传输的值对象中 网络:数据传输对象。 详细DTO
您也可以使用推土机:
Dozer是Java Bean到Java Bean的映射器,可将数据从一个对象递归复制到另一个对象。 详细Dozer
如何将{em>推土机与Spring Boot一起使用
推土机注释映射documentation