Question

我的文本在括号之间有1个或多个2个句点。

K= 'Product will be hot(These cooking instructions were developed using an 100 watt microwave oven. For lower wattage ovens, up to an additional 2 minutes cooking time may be required).'

我想提取或消除整个文本。我已经尝试过

re.search(r'\((.*?)+\)',K).group(1)

和

K[K.find("(")+1:K.find(")")]

但它们都不返回文本

Answer 1

您可以使用表达式：

(?<=\()[^()]*(?=\))

尝试实时表达here。

使用re.findall查找您感兴趣的文本。

import re
K = 'Product will be hot(These cooking instructions were developed using an 100 watt microwave oven. For lower wattage ovens, up to an additional 2 minutes cooking time may be required).'
print(re.findall(r'(?<=\()[^()]*(?=\))',K))

打印：

['These cooking instructions were developed using an 100 watt microwave oven. For lower wattage ovens, up to an additional 2 minutes cooking time may be required']

或者将字符集包装到捕获组中

import re
K = 'Product will be hot(These cooking instructions were developed using an 100 watt microwave oven. For lower wattage ovens, up to an additional 2 minutes cooking time may be required).'
print(re.search(r'(?<=\()([^()]*)(?=\))',K).group(1))

打印：

These cooking instructions were developed using an 100 watt microwave oven. For lower wattage ovens, up to an additional 2 minutes cooking time may be required

Answer 2

IIUC，以下正则表达式将删除包含一个或多个句点的括号之间的任何文本，以及括号本身：

re.sub('\(.*?\.+.*\)','', K)

示例：

>>> re.sub('\(.*?\.+.*\)','', K)
'Product will be hot.'

要提取文本而不是删除文本，请使用带有相同正则表达式的re.findall：

>>> re.findall('\(.*?\.+.*\)', K)
['(These cooking instructions were developed using an 100 watt microwave oven. For lower wattage ovens, up to an additional 2 minutes cooking time may be required)']

[编辑] ：若要匹配一组以上的大括号，请执行以下操作：

K='Product will be hot (These cooking instructions were. developed using an 100 watt microwave oven). For lower wattage ovens (up to an additional 2 minutes. cooking time may be required).'

>>> re.findall('\(.*?\.+.*?\)', K)
['(These cooking instructions were. developed using an 100 watt microwave oven)', '(up to an additional 2 minutes. cooking time may be required)']

>>> re.sub('\(.*?\.+.*?\)', '', K)
'Product will be hot . For lower wattage ovens .'

Answer 3

请注意，如果括号中有两个以上的句点，则不会进行替换；而且，不会合并两个括号中的节，从而消除了它们之间的文本：

>>> re.sub(r'\(([^.(]*\.){1,2}[^.()]*\)',"",K)
'Product will be hot.'

如果您还想删除两个以上带有括号的部分，则可以简单地将{1,2}替换为+：

>>> re.sub(r'\(([^.(]*\.)+[^.()]*\)',"",K)

正则表达式，返回括号之间有1个或多个句点的文本

3 个答案: