Question

我有例如 10％， 13％的示例，我必须将它们转换为 分别为10％和13％。

我该怎么做，我必须将长字符串中的这个字符串与之匹配，并需要将其转换为数字，下面的代码可以找到

10％和10％如何找到10％并将其转换为数字

代码

public StringBuilder extractPercentage(string html)
{
    StringBuilder formattedString = new StringBuilder();
    foreach (Match m in Regex.Matches(html, @"\d+\%|\s\bpercent\b)"))
    {
        var a = m.Value;
        formattedString.Append(m.Value + "<br/>");
    }
    return formattedString;
}

结果：

100％-是

100％是

我在这里有两种情况：识别数量并带有百分比并转换为数字

Answer 1

下面的代码应该可以满足您的需求：

  static string ParseEnglish(string number)
    {

        number= number.Replace("percent", "").Trim();

        string[] words = number.ToLower().Split(new char[] { ' ', '-', ',' }, StringSplitOptions.RemoveEmptyEntries);
        string[] ones = { "one", "two", "three", "four", "five", "six", "seven", "eight", "nine" };
        string[] teens = { "eleven", "twelve", "thirteen", "fourteen", "fifteen", "sixteen", "seventeen", "eighteen", "nineteen" };
        string[] tens = { "ten", "twenty", "thirty", "forty", "fifty", "sixty", "seventy", "eighty", "ninety" };
        Dictionary<string, int> modifiers = new Dictionary<string, int>() {
    {"billion", 1000000000},
    {"million", 1000000},
    {"thousand", 1000},
    {"hundred", 100}
};

        if (number == "eleventy billion")
            return int.MaxValue.ToString(); // 110,000,000,000 is out of range for an int!

        int result = 0;
        int currentResult = 0;
        int lastModifier = 1;

        foreach (string word in words)
        {
            if (modifiers.ContainsKey(word))
            {
                lastModifier *= modifiers[word];
            }
            else
            {
                int n;

                if (lastModifier > 1)
                {
                    result += currentResult * lastModifier;
                    lastModifier = 1;
                    currentResult = 0;
                }

                if ((n = Array.IndexOf(ones, word) + 1) > 0)
                {
                    currentResult += n;
                }
                else if ((n = Array.IndexOf(teens, word) + 1) > 0)
                {
                    currentResult += n + 10;
                }
                else if ((n = Array.IndexOf(tens, word) + 1) > 0)
                {
                    currentResult += n * 10;
                }
                else if (word != "and")
                {
                    throw new ApplicationException("Unrecognized word: " + word);
                }
            }
        }
        int ReturnValue = result + currentResult * lastModifier;
        return ReturnValue.ToString () + "%";
    }

此答案是对本帖子答案的修改： Convert words (string) to Int

将文本格式百分比值转换为数值

1 个答案: