Question

我正在尝试使用通过电子邮件和密码进行身份验证的android系统创建一个注册页面，然后将其他数据注册到实时数据库中。当我单击“注册”按钮时，电子邮件和其他数据将输入到身份验证中。但其他数据不会处理到实时数据库中。

我也没有看到任何错误。

这是MainActivity.java文件

public class MainActivity extends AppCompatActivity implements View.OnClickListener {


private TextView txtName, txtEmail, txtPassword, txtMobile;
private Spinner spinner;
private ProgressBar progressBar;
private FirebaseAuth mAuth;
@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);

    txtName = findViewById(R.id.txtName);
    txtEmail = findViewById(R.id.txtEmail);
    txtPassword = findViewById(R.id.txtPassword);
    txtMobile = findViewById(R.id.txtMobile);

    progressBar = findViewById(R.id.progressBar);
    progressBar.setVisibility(View.GONE);

    spinner = findViewById(R.id.spinner);

    mAuth=FirebaseAuth.getInstance();

    findViewById(R.id.btnRegister).setOnClickListener(this);
}

@Override
public void onClick(View view) {
    switch (view.getId()){
        case R.id.btnRegister:
        registerUser();
        break;
    }
}

@Override
protected void onStart() {
    super.onStart();
    if(mAuth.getCurrentUser()!=null){

        //handle the already login user

    }
}

private void registerUser(){
    final String name = txtName.getText().toString().trim();
    final String email = txtEmail.getText().toString().trim();
    String password = txtPassword.getText().toString().trim();
    final String mobile = txtMobile.getText().toString().trim();
    final String gender = spinner.getSelectedItem().toString();


    if(name.isEmpty()) {
        txtName.setError("Name required!");
        txtName.requestFocus();
        return;
    }
    if(!Patterns.EMAIL_ADDRESS.matcher(email).matches()) {
        txtEmail.setError("Enter a valid email!");
        txtName.requestFocus();
        return;
    }

    if(password.isEmpty()) {
        txtPassword.setError("Password Required!");
        txtPassword.requestFocus();
        return;
    }

    if(password.length()<6) {
        txtPassword.setError("Strong password required");
        txtPassword.requestFocus();
        return;
    }

    if(mobile.isEmpty()) {
        txtMobile.setError("Mobile Required!");
        txtMobile.requestFocus();
        return;
    }
    progressBar.setVisibility(View.VISIBLE);
    mAuth.createUserWithEmailAndPassword(email,password)
            .addOnCompleteListener(new OnCompleteListener<AuthResult>() {
                @Override
                public void onComplete(@NonNull Task<AuthResult> task) {

                    if(task.isSuccessful()){
                        //Store additional fields into firebase database
                        User user = new User(
                                  name,
                                  email,
                                  mobile,
                                  gender

                        );

                        FirebaseDatabase.getInstance().getReference("Users")
                                .child(FirebaseAuth.getInstance().getCurrentUser().getUid())
                                .setValue(user).addOnCompleteListener(new OnCompleteListener<Void>() {
                            @Override
                            public void onComplete(@NonNull Task<Void> task) {
                                progressBar.setVisibility(View.GONE);
                                if(task.isSuccessful()){
                                    Toast.makeText(MainActivity.this,"User Registered Successfully!", Toast.LENGTH_LONG).show();
                                }else{
                                    Toast.makeText(MainActivity.this,"Error: Registration failed!", Toast.LENGTH_LONG).show();

                                }

                            }
                        });

                    }else{
                        Toast.makeText(MainActivity.this, task.getException().getMessage(), Toast.LENGTH_LONG).show();
                    }
                }
            });
}

}

这是User.java文件

public class User {
public String name, email, phone, gender;


public User(){

}

public User(String name, String email, String phone, String gender) {
    this.name = name;
    this.email = email;
    this.phone = phone;
    this.gender = gender;
}
}

Answer 1

https://firebase.google.com/docs/database/security/

您是否检查了项目的实时数据库安全规则？首先，Google给您2个选择。其中一种是第三方不允许的锁定模式，另一种是测试模式允许所有人使用。您可以在开发时使用测试模式，但是出于安全原因，您应该制定自己的规则。

Firebase Auth EmailAndPassword和实时数据库错误

1 个答案: