当我单击标记时,不会出现弹出窗口。我收到以下错误

时间:2018-08-06 12:18:26

标签: javascript d3.js leaflet

我尝试复制并粘贴错误并找到了资源,但我实际上无法理解它是什么。 我遇到了这个弹出问题,请务必帮我解决。 我要附加代码段以及控制台日志中弹出的错误。

代码段:

for (var i=0; i<quakePoints.length; i++) {

        var lon = quakePoints[i][1];
        var lat = quakePoints[i][0];
        var popupText = quakePoints[i][2];
        var markerLocation = new L.LatLng(lat, lon);
        var marker = new L.marker(markerLocation);
        marker.bindPopup(popupText).addTo(map);

    }

错误:

leaflet.js:7 Uncaught TypeError: Failed to execute 'appendChild' on 'Node': parameter 1 is not of type 'Node'.
        at e._updateContent (leaflet.js:7)
        at e.update (leaflet.js:7)
        at e.onAdd (leaflet.js:7)
        at e._layerAdd (leaflet.js:6)
        at e.addLayer (leaflet.js:6)
        at e.openPopup (leaflet.js:7)
        at e.openPopup (leaflet.js:7)
        at e.togglePopup (leaflet.js:7)
        at e.fireEvent (leaflet.js:6)
        at e._onMouseClick (leaflet.js:7)

错误-使用leaflet-src.js

leaflet-src.js:4046 Uncaught TypeError: Failed to execute 'appendChild' on 'Node': parameter 1 is not of type 'Node'.
    at NewClass._updateContent (leaflet-src.js:4046)
    at NewClass.update (leaflet-src.js:3974)
    at NewClass.onAdd (leaflet-src.js:3899)
    at NewClass._layerAdd (leaflet-src.js:2265)
    at NewClass.addLayer (leaflet-src.js:1723)
    at NewClass.openPopup (leaflet-src.js:4172)
    at NewClass.openPopup (leaflet-src.js:4197)
    at NewClass.togglePopup (leaflet-src.js:4215)
    at NewClass.fireEvent (leaflet-src.js:466)
    at NewClass._onMouseClick (leaflet-src.js:3738)

编辑,附加示例数据

var quakePoints = [
    [17.123184,79.208824,1.7345],
    [19.123184,76.208824,2.7345],
    [18.123184,69.208824,2.7345],
    [21.123184,70.208824,3.7345],
    [23.123184,72.208824,2.6645],
    [22.123184,77.208824,1.2245],
    [24.123184,85.208824,2.7345],
    [18.123184,78.208824,1.7345],
    [11.123184,89.208824,1.7345]];

1 个答案:

答案 0 :(得分:3)

根据您的另一个问题,quakePoints数组如下:

var quakePoints = [
    [17.123184,79.208824,1.7345],
    ...
];

这意味着popupText在这里...

    var popupText = quakePoints[i][2];

...获取值1.7345,但获取为 Number ,而不是 String

后来,Leaflet正在运行this piece of code,内部参数content设置为 Number 1.7345

    if (typeof content === 'string') {
        node.innerHTML = content;
    } else {
        // snip
        node.appendChild(content);
    }

该参数不是一个 String ,因此它将尝试将其作为HTMLElement处理。

请仔细阅读definition of the bindPopup method from the Leaflet API reference

  

bindPopup(<String|HTMLElement|Function|Popup> content, <Popup options> options?)

     

使用传递的内容将弹出窗口绑定到该层,并设置必要的事件侦听器。如果传递了Function,它将接收该图层作为第一个参数,并应返回StringHTMLElement

请注意,bindPopup的第一个参数必须是StringHTMLElement,返回Function或{{ 1}}或String的实例。您正在传递HTMLElement,但这些都不是,所以您的问题实际上是GIGO的情况。

这里的方法是确保您传递的是Popup

例如与String()

Number

或例如与Number.toString()

String