在Ionic3和Ionic4中处理硬件后退按钮

时间:2018-08-06 05:08:44

标签: ionic3 ionic4

请在ionic3中找到以下有关Android硬件后退按钮操作的代码。当Ionic4使用角路由进行导航时,后退按钮的弹出事件将如何发生?如果要跳至最后一页,可以使用以下代码this.navCtrl.goBack('/products');。 但是我们如何在ionic4中将其用于android硬件后退按钮操作?

Ionic3硬件后退按钮动作

this.platform.registerBackButtonAction(() => {
    let activePortal = this.ionicApp._loadingPortal.getActive() ||
        this.ionicApp._modalPortal.getActive() ||
        this.ionicApp._toastPortal.getActive() ||
        this.ionicApp._overlayPortal.getActive();
    if (activePortal) {
        activePortal.dismiss();
    } else {
        if (this.nav.canGoBack()) {
            ***this.nav.pop();***
        } else {
            if (this.nav.getActive().name === 'LoginPage') {
                this.platform.exitApp();
            } else {
                this.generic.showAlert("Exit", "Do you want to exit the app?", this.onYesHandler, this.onNoHandler, "backPress");
            }
        }
    }
});

7 个答案:

答案 0 :(得分:8)

更新:此问题已在dfac9dc

中修复

Related: ionic4 replacement for registerBackButtonAction


这在GitHubIconic ForumTwitter中被跟踪
在没有正式修复之前,您可以使用下面的解决方法。


使用 platform.backButton.subscribe(请参阅here platform.backButton.subscribeWithPriority(0, ...) 让离子处理程序关闭所有模态/警报/ ... < / strong> ,当its own back button is pressed和新的router-controller一起使用时,离子代码将使用如下代码:

import { ViewChild } from '@angular/core';
import {
  IonRouterOutlet,
  Platform
} from '@ionic/angular';
import {
  Router
} from '@angular/router';

//...

/* get a reference to the used IonRouterOutlet 
assuming this code is placed in the component
that hosts the main router outlet, probably app.components */
@ViewChild(IonRouterOutlet) routerOutlet: IonRouterOutlet;

constructor(
  ...
  /* if this is inside a page that was loaded into the router outlet,
  like the start screen of your app, you can get a reference to the 
  router outlet like this:
  @Optional() private routerOutlet: IonRouterOutlet, */
  private router: Router,
  private platform: Platform
  ...
) {
  this.platform.backButton.subscribeWithPriority(0, () => {
    if (this.routerOutlet && this.routerOutlet.canGoBack()) {
      this.routerOutlet.pop();
    } else if (this.router.url === '/LoginPage') {
      this.platform.exitApp(); 

      // or if that doesn't work, try
      navigator['app'].exitApp();
    } else {
      this.generic.showAlert("Exit", "Do you want to exit the app?", this.onYesHandler, this.onNoHandler, "backPress");
    }
  });
}

答案 1 :(得分:7)

尝试一下: app.comonent.ts

import { Component, ViewChildren, QueryList } from '@angular/core';
import { Platform, ModalController, ActionSheetController, PopoverController, IonRouterOutlet, MenuController } from '@ionic/angular';
import { SplashScreen } from '@ionic-native/splash-screen/ngx';
import { StatusBar } from '@ionic-native/status-bar/ngx';
import { Router } from '@angular/router';
import { Toast } from '@ionic-native/toast/ngx';

@Component({
    selector: 'app-root',
    templateUrl: 'app.component.html'
})
export class AppComponent {

    // set up hardware back button event.
    lastTimeBackPress = 0;
    timePeriodToExit = 2000;

    @ViewChildren(IonRouterOutlet) routerOutlets: QueryList<IonRouterOutlet>;

    constructor(
        private platform: Platform,
        private splashScreen: SplashScreen,
        private statusBar: StatusBar,
        public modalCtrl: ModalController,
        private menu: MenuController,
        private actionSheetCtrl: ActionSheetController,
        private popoverCtrl: PopoverController,
        private router: Router,
        private toast: Toast) {

        // Initialize app
        this.initializeApp();

        // Initialize BackButton Eevent.
        this.backButtonEvent();
    }

    // active hardware back button
    backButtonEvent() {
        this.platform.backButton.subscribe(async () => {
            // close action sheet
            try {
                const element = await this.actionSheetCtrl.getTop();
                if (element) {
                    element.dismiss();
                    return;
                }
            } catch (error) {
            }

            // close popover
            try {
                const element = await this.popoverCtrl.getTop();
                if (element) {
                    element.dismiss();
                    return;
                }
            } catch (error) {
            }

            // close modal
            try {
                const element = await this.modalCtrl.getTop();
                if (element) {
                    element.dismiss();
                    return;
                }
            } catch (error) {
                console.log(error);

            }

            // close side menua
            try {
                const element = await this.menu.getOpen();
                if (element) {
                    this.menu.close();
                    return;

                }

            } catch (error) {

            }

            this.routerOutlets.forEach((outlet: IonRouterOutlet) => {
                if (outlet && outlet.canGoBack()) {
                    outlet.pop();

                } else if (this.router.url === '/home') {
                    if (new Date().getTime() - this.lastTimeBackPress < this.timePeriodToExit) {
                        // this.platform.exitApp(); // Exit from app
                        navigator['app'].exitApp(); // work in ionic 4

                    } else {
                        this.toast.show(
                            `Press back again to exit App.`,
                            '2000',
                            'center')
                            .subscribe(toast => {
                                // console.log(JSON.stringify(toast));
                            });
                        this.lastTimeBackPress = new Date().getTime();
                    }
                }
            });
        });
    }
}

在ionic v4 beta中对我有用

答案 2 :(得分:1)

对于Ionic4,我尝试了这种方法,对我来说效果很好。

  

进入视图时,我会将其订阅到变量中,离开视图时将其取消订阅。这样返回按钮上退出的应用程序将仅针对该特定页面执行。

constructor(private platform: Platform){}
backButtonSubscription;
ionViewWillEnter() {
  this.backButtonSubscription = this.platform.backButton.subscribe(async () => {
  navigator['app'].exitApp();
  });
 }
}
ionViewDidLeave() {
 this.backButtonSubscription.unsubscribe();
}

答案 3 :(得分:0)

这就是我在我的应用程序中所做的工作(使用ionic4在Android应用程序中开发)。因此,当用户在Android手机上单击回来时,应用程序退出。

示例代码:

import { Component, AfterViewInit, OnDestroy } from '@angular/core';
import { Platform } from '@ionic/angular';
@Component({
  selector: 'app-root',
  templateUrl: 'app.component.html',
  styleUrls: ['app.component.scss']
})
export class AppComponent implements AfterViewInit, OnDestroy {

  constructor(private platform: Platform) { }
  backButtonSubscription;
  ngAfterViewInit() {
    this.backButtonSubscription = this.platform.backButton.subscribe(() => {
      // add logic here if you want to ask for a popup before exiting
      navigator['app'].exitApp();
    });
  }

  ngOnDestroy() {
    this.backButtonSubscription.unsubscribe();
  }
}

源:here

答案 4 :(得分:0)

使用cordova事件“后退按钮”

document.addEventListener("backbutton", youFunction, false);

我使用ionic4 / vue并有效

答案 5 :(得分:0)

这是我在 Ionic 5项目上的工作代码。 使用Cordova / PhoneGap

import {Component} from '@angular/core';
import {ToastService} from './_services/toast.service';

@Component({
  selector: 'app-root',
  templateUrl: 'app.component.html',
  styleUrls: ['app.component.scss']
})
export class AppComponent {
  constructor(private toastCtrl: ToastService) {
    this.backButton();
  }
  backButton() {
      const that = this;
      let lastTimeBackPress = 0;
      const timePeriodToExit = 2000;
      function onBackKeyDown(e) {
          e.preventDefault();
          e.stopPropagation();
          if (new Date().getTime() - lastTimeBackPress < timePeriodToExit) {
              navigator.app.exitApp();
          } else {
              that.presentToast();
              lastTimeBackPress = new Date().getTime();
          }
      }
      document.addEventListener('backbutton', onBackKeyDown, false);
  }
  presentToast() {
    const toast = this.toastCtrl.create({
      message: "Press again to exit",
      duration: 3000,
      position: "middle"
    });
  toast.present();
  }
}

或查看此内容:- https://thaaimozhikalvi.com/2020/05/28/ionic-5-double-tab-back-button-to-exit-using-cordova-phonegap/

答案 6 :(得分:0)

在Ionic 4中自定义Android后退按钮 ... ...每页明智地退回。

步骤1:import { Platform, NavController } from '@ionic/angular';

第2步:constructor(public navCtrl: NavController){}

第3步:

 private async onBack() {
    this.navCtrl.navigateBack('/project-details');
  }

第4步:

 this.platform.backButton.subscribe(()=>{
        this.onBack();
      });