示例XML:
<?xml version="1.0" encoding="UTF-8"?>
<entry>
<author>
<name>/u/Kobe_to_Boston</name>
<uri>https://www.reddit.com/user/Kobe_to_Boston</uri>
</author>
<id>t3_94t5in</id>
<link href="https://www.reddit.com/r/hiphopheads/comments/94q6ks/travis_scott_stop_trying_to_be_god_ft_kid_cudi/" />
<updated>2018-08-05T16:38:29+00:00</updated>
<title>The Weeknd - The Hills</title>
</entry>
使用Scala XML Library。我正在尝试从Reddit RSS feed获取各种数据。
例如,获取有关Reddit帖子标题的信息。以下代码是:
val redditPostTitle = (XML.loadString(xmlContent) \ "entry" \ "title").head.text
//assume xmlContent variable is the contains the XML above
上面的作品。
现在,问题是,我想从“ link href”标签中检索数据。我尝试了各种组合:
val redditPostUrl = (XML.loadString(xmlContent) \ "entry" \ "link href").head.text
但是我得到一个空字符串。我想返回的是:
"https://www.reddit.com/r/hiphopheads/comments/94q6ks/travis_scott_stop_trying_to_be_god_ft_kid_cudi/
已解决:解决方案是:
(XML.loadString(hhhContent) \ "entry" \\ "link" \\ "@href").text
答案 0 :(得分:2)
这很好:
object Example extends App {
val feed=
<entry>
<author>
<name>/u/Kobe_to_Boston</name>
<uri>https://www.reddit.com/user/Kobe_to_Boston</uri>
</author>
<id>t3_94t5in</id>
<link href="https://www.reddit.com/r/hiphopheads/comments/94q6ks/travis_scott_stop_trying_to_be_god_ft_kid_cudi/" />
<updated>2018-08-05T16:38:29+00:00</updated>
<title>The Weeknd - The Hills</title>
</entry>
println(feed \\ "link" \ "@href")
}