Python正则表达式返回括号内字符串的位置

Question

我试图使用正则表达式来获取字符串在括号内的位置。

例如，我想获得“家得宝”的位置；

sent = "Sales to two of the segment's customers, The Home Depot and Lowe's Home Improvement Warehouse, accounted for greater than 10% of the Corporation's consolidated sales for 2004, 2003, and 2002."

regex_ = re.compile("Sales to two of the segment's customers, The (Home Depot)

但是

regex_.search(sent).span()

返回(0, 55)而不是(45, 55)

由于可能发送了多个“家得宝”，所以我无法使用re.search('Home Depot', sent).span()，这可能无法返回我要寻找的家得宝的确切位置。

Answer 1

如果要获取括号中文本的位置，则需要指定要与第一组匹配作为span()的参数：

sent = "Sales to two of the segment's customers, The Home Depot and Lowe's Home Improvement Warehouse, accounted for greater than 10% of the Corporation's consolidated sales for 2004, 2003, and 2002."

regex_ = re.compile("Sales to two of the segment's customers, The (Home Depot)

regex_.search(sent).span(1)

请参阅match objects and span上的python文档。

Answer 2

使用积极的眼光：

sent = "Sales to two of the segment's customers, The Home Depot and Lowe's Home Improvement Warehouse, accounted for greater than 10% of the Corporation's consolidated sales for 2004, 2003, and 2002."
regex_ = re.compile(r"(?<=Sales to two of the segment's customers, The )Home Depot")
print(regex_.search(sent).span())

输出：

(45, 55)

Answer 3

您的正则表达式正确。但是，您需要的是整个比赛的位置，而不是子比赛的位置。要获取第一个子匹配项的位置，请使用span(1)

>>> regex_ = re.compile("Sales to two of the segment's customers, The (Home Depot)")
>>> regex_.search(sent).span(1)
(45, 55)