Question

我想通过以下代码访问资源文件夹中的.txt文件

void Start () {
    TextAsset txtAsset = (TextAsset)Resources.Load("Dialogue0", typeof(TextAsset));
    string dialogue = txtAsset.text;

    lines = new List<DialogueLine>();

    LoadDialogue(dialogue);
} 

void LoadDialogue(string filename)
{
    string line;
    StreamReader r = new StreamReader(filename);

    using (r)
    {
        do
        {
            line = r.ReadLine();
            if (line != null)
            {
                string[] lineData = line.Split('|');
                if (lineData[0] == "Player")
                {
                    DialogueLine lineEntry = new DialogueLine(lineData[0], "", 0,0, "");
                    lineEntry.options = new string[lineData.Length - 1];
                    for (int i = 1; i < lineData.Length; i++)
                    {
                        lineEntry.options[i - 1] = lineData[i];
                    }
                    lines.Add(lineEntry);
                }
                else
                {
                    DialogueLine lineEntry = new DialogueLine(lineData[0], lineData[1], int.Parse(lineData[2]), int.Parse(lineData[3]), lineData[4]);
                    lines.Add(lineEntry);
                }
            }
        }
        while (line != null);
        r.Close();
    }
}

但总是会出现错误：

ArgumentException: Empty path not allowed

System.IO.StreamReader..ctor (System.String path, System.Text.Encoding encoding, 
            Boolean detectEncodingFromByteOrderMarks, Int32 bufferSize) 
(at /Users/builduser/buildslave/mono/build/mcs/class/corlib/System.IO/StreamReader.cs:159)

System.IO.StreamReader..ctor (System.String path)
(wrapper remoting-invoke-with-check) System.IO.StreamReader:.ctor (string)

DialogueParser.LoadDialogue (System.String filename) (at Assets/Script/DialogueParser.cs:54)

DialogueParser.Start () (at Assets/Script/DialogueParser.cs:44)

The .txt file is really exist, named "Dialogue0.txt"

我已经搜索了一段时间，但没有找到解决问题的方法。

编辑：Contents of dialogue0.txt

Answer 1

“ Dialogue0.txt”的内容将用作文件名。因此，请检查Dialogue0.txt的内容。打印“对话”，发现会发生什么。也许最后有一个空行。

更新：

这也许是一个统一的问题。您可以阅读TextAsset.text is "" although the file does have content以获得更多详细信息。

If your Dialogue0.txt contain slanted apostrophe , Changing this to a regular vertical apostrophe (ascii 0x27) make the file load correctly!

对于其他情况，您可以尝试此操作或更改统一版本。

 string content = lang.text;
 if(content == "")
 content = System.Text.Encoding.Default.GetString(lang.bytes);

Answer 2

我认为您应该使用扩展名“ Dialogue0.txt”，而不只是“ Dialogue0”：

TextAsset txtAsset = (TextAsset)Resources.Load("Dialogue0.txt", typeof(TextAsset));

Answer 3

您始终可以打印出所有资源以从API级别签出。

var allResources = Resources.LoadAll（“ [PathRelativeToResourcesDir]”）

参数异常：不允许空路径

3 个答案: