BeautifulSoup get_text返回NoneType对象

时间:2018-08-04 17:11:10

标签: python-3.x web-scraping beautifulsoup

我正在尝试BeautifulSoup进行网页抓取,并且需要从此webpage中提取标题,尤其是从“更多”标题部分中。这是我到目前为止尝试使用的代码。

import requests
from bs4 import BeautifulSoup
from csv import writer

response = requests.get('https://www.cnbc.com/finance/?page=1')

soup = BeautifulSoup(response.text,'html.parser')

posts = soup.find_all(id='pipeline')

for post in posts:
    data = post.find_all('li')
    for entry in data:
        title = entry.find(class_='headline')
        print(title)

运行此代码,将以以下输出格式显示页面中的所有标题:

<div class="headline">
<a class=" " data-nodeid="105372063" href="/2018/08/02/after-apple-rallies-to-1-trillion-even-the-uber-bullish-crowd-on-wal.html">
           {{{*HEADLINE TEXT HERE*}}}
</a> </div>

但是,如果在上面的代码中获取标题时使用get_text()方法,则只会得到前两个标题。

title = entry.find(class_='headline').get_text()

随后出现此错误:

Traceback (most recent call last):
  File "C:\Users\Tanay Roman\Documents\python projects\scrapper.py", line 16, in <module>
    title = entry.find(class_='headline').get_text()
AttributeError: 'NoneType' object has no attribute 'get_text'

为什么添加get_text()方法仅返回部分结果。而我该如何解决呢?

1 个答案:

答案 0 :(得分:2)

您误解了错误消息。并不是.get_text()调用返回一个NoneType对象,而是NoneType类型的对象没有该方法。

只有一个类型NoneType的对象,值None。在这里它是由entry.find(class_='headline')返回的,因为它无法在entry中找到与搜索条件匹配的元素。换句话说,对于该entry元素,没有类别为headline的子元素。

有两个这样的<li>元素,一个元素的ID为nativedvriver3,另一个元素的元素为nativedvriver9,这两个元素都将导致该错误。您需要先检查是否存在匹配的元素:

for entry in data:
    headline = entry.find(class_='headline')
    if headline is not None:
        title = headline.get_text()

如果您使用CSS selector,则可以轻松得多:

headlines = soup.select('#pipeline li .headline')
for headline in headlines:
    headline_text = headline.get_text(strip=True)
    print(headline_text)

这将产生:

>>> headlines = soup.select('#pipeline li .headline')
>>> for headline in headlines:
...     headline_text = headline.get_text(strip=True)
...     print(headline_text)
...
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