Question

我有一个Node.js博客API。目前，我使用Insomnia发布了一个包含标题和内容的Json对象。我现在想在帖子中添加图片。

我的Json看起来像这样：

{
    "post": {
        "title": "My title",
        "content": "This content",
        "image": "/path/to/image.jpg"
    }
}

我的addPost函数包含：

newPost.image.data = fs.readFileSync(newPost.image);
newPost.image.contentType = 'image/jpeg';

// Let's sanitize inputs
newPost.title = sanitizeHtml(newPost.title);
newPost.content = sanitizeHtml(newPost.content);

我收到此错误：

TypeError: Cannot create property 'data' on string '/path/to/image.jpg'

我认为这是因为newPost.image.data需要一个对象，但是fs.readFileSync(newPost.image)是一个字符串。我不知道该如何处理。有人可以提供任何建议吗？

完整的addPost功能：

完整的邮政编码：

PostController.addPost = async (req, res) => {

    try {
        if (!req.body.post.title || !req.body.post.content) {
            res.status(403).end();
        }

        const newPost = new Post(req.body.post);

        newPost.image = {};
        newPost.image.data = fs.readFileSync(newPost.image);
        newPost.image.type = 'image/jpeg';

        // Let's sanitize inputs
        newPost.title = sanitizeHtml(newPost.title);
        newPost.content = sanitizeHtml(newPost.content);

        newPost.slug = slug(newPost.title.toLowerCase(), { lowercase: true });
        newPost.cuid = cuid();

        newPost.save((err, saved) => {
            if (err) {
                res.status(500).send(err);
            }
            res.json({ post: saved });
        });
    }
    catch (err) {
        console.log(err);
    }
}

发布

import mongoose from 'mongoose';
const Schema = mongoose.Schema;

const postSchema = new Schema({
    title: { type: 'String', required: true },
    content: { type: 'String', required: true },
    image: { data: Buffer, type: 'String', required: true }, //added when trying to get the image to post
    slug: { type: 'String', required: true },
    cuid: { type: 'String', required: true },
    dateAdded: { type: 'Date', default: Date.now, required: true },

}）;

let Post = mongoose.model('Post', postSchema);

export default Post;

Answer 1

将newPost.image = {}初始化为空对象，然后分配值

newPost.image.data = fs.readFileSync(newPost.image); newPost.image.contentType = 'image/jpeg';

TypeError：无法在字符串上创建属性“ data”

1 个答案: