Question

此刻我有多个要收集为1的查询，只有日期范围在变化，它们是相同的：

查询1：

SELECT COUNT(simp_posts.ID)
FROM simp_posts
INNER JOIN simp_postmeta
ON ( simp_posts.ID = simp_postmeta.post_id )
WHERE ( ( simp_postmeta.meta_key = '_schedule_end' AND simp_postmeta.meta_value = '0' AND simp_posts.post_status = 'wc-active'))
OR ( ( simp_postmeta.meta_key = '_schedule_end' AND simp_postmeta.meta_value > '2018-08-01 23:33:51' AND simp_posts.post_status = 'wc-active'))
OR ( ( simp_postmeta.meta_key = '_schedule_end' AND simp_postmeta.meta_value > '2018-08-01 23:33:51' AND simp_posts.post_status = 'wc-pending-cancel'))

查询2：

SELECT COUNT(simp_posts.ID)
FROM simp_posts
INNER JOIN simp_postmeta
ON ( simp_posts.ID = simp_postmeta.post_id )
WHERE ( ( simp_postmeta.meta_key = '_schedule_end' AND simp_postmeta.meta_value = '0' AND simp_posts.post_status = 'wc-active'))
OR ( ( simp_postmeta.meta_key = '_schedule_end' AND simp_postmeta.meta_value > '2018-09-01 23:33:51' AND simp_posts.post_status = 'wc-active'))
OR ( ( simp_postmeta.meta_key = '_schedule_end' AND simp_postmeta.meta_value > '2018-09-01 23:33:51' AND simp_posts.post_status = 'wc-pending-cancel'))

查询3：

SELECT COUNT(simp_posts.ID)
FROM simp_posts
INNER JOIN simp_postmeta
ON ( simp_posts.ID = simp_postmeta.post_id )
WHERE ( ( simp_postmeta.meta_key = '_schedule_end' AND simp_postmeta.meta_value = '0' AND simp_posts.post_status = 'wc-active'))
OR ( ( simp_postmeta.meta_key = '_schedule_end' AND simp_postmeta.meta_value > '2018-10-01 23:33:51' AND simp_posts.post_status = 'wc-active'))
OR ( ( simp_postmeta.meta_key = '_schedule_end' AND simp_postmeta.meta_value > '2018-10-01 23:33:51' AND simp_posts.post_status = 'wc-pending-cancel'))

我希望将这些查询合并为一个，并使其结果为3行，每个计数的结果都为1。例如我会得到： 182 183 194

谢谢您的帮助

Answer 1

在where中具有通用条件，并有条件地汇总日期范围。请注意@Tim在评论中提到的内容。如果计数必须互斥，请在meta_value表达式中包含一个case范围。

SELECT COUNT(CASE WHEN simp_postmeta.meta_value > '2018-08-01 23:33:51' 
                  THEN simp_posts.ID END)
,COUNT(CASE WHEN simp_postmeta.meta_value > '2018-09-01 23:33:51' 
            THEN simp_posts.ID END)
,COUNT(CASE WHEN simp_postmeta.meta_value > '2018-10-01 23:33:51' 
            THEN simp_posts.ID END)
FROM simp_posts
INNER JOIN simp_postmeta ON simp_posts.ID = simp_postmeta.post_id
WHERE simp_postmeta.meta_key = '_schedule_end' 
AND simp_posts.post_status IN ('wc-active','wc-pending-cancel')

Answer 2

在MySQL中，您可以通过将SUM()与布尔值结合使用来简化答案。

您的逻辑很复杂。我认为它可以简化为：

SELECT SUM((pm.meta_value = '0' AND p.post_status = 'wc-active') or pm.meta_value > '2018-09-01 23:33:51'),
       SUM((pm.meta_value = '0' AND p.post_status = 'wc-active') or pm.meta_value > '2018-10-01 23:33:51'),
SUM((pm.meta_value = '0' AND p.post_status = 'wc-active') or pm.meta_value > '2018-10-01 23:33:51')
FROM simp_posts p INNER JOIN
     simp_postmeta pm
     ON p.ID = pm.post_id
WHERE pm.meta_key = '_schedule_end' AND
      p.post_status IN ('wc-active', 'wc-pending-cancel')

单个查询中包含多个MySQL

2 个答案: