当我尝试运行命令ionic cordova run android
时,我在cmd中遇到了一些错误
audio: Failed to create voice `adc'
(node:4940) UnhandledPromiseRejectionWarning: CordovaError: Failed to execute shell command "getprop,dev.bootcomplete"" on device: Error: C:\Users\hi\AppData\Local\Android\Sdk\platform-tools\adb.exe: Command failed with exit code 1 Error output:
error: device still authorizing
at D:\product\project-1\frontend\platforms\android\cordova\lib\Adb.js:88:25
at _rejected (D:\product\project-1\frontend\platforms\android\cordova\node_modules\q\q.js:864:24)
at D:\product\project-1\frontend\platforms\android\cordova\node_modules\q\q.js:890:30
at Promise.when (D:\product\project-1\frontend\platforms\android\cordova\node_modules\q\q.js:1142:31)
at Promise.promise.promiseDispatch (D:\product\project-1\frontend\platforms\android\cordova\node_modules\q\q.js:808:41)
at D:\product\project-1\frontend\platforms\android\cordova\node_modules\q\q.js:624:44
at runSingle (D:\product\project-1\frontend\platforms\android\cordova\node_modules\q\q.js:137:13)
at flush (D:\product\project-1\frontend\platforms\android\cordova\node_modules\q\q.js:125:13)
at _combinedTickCallback (internal/process/next_tick.js:131:7)
at process._tickCallback (internal/process/next_tick.js:180:9)
(node:4940) UnhandledPromiseRejectionWarning: Unhandled promise rejection. This error originated either by throwing inside of an async function without a catch block, or by rejecting a promise which was not handled with .catch(). (rejection id: 1)
(node:4940) [DEP0018] DeprecationWarning: Unhandled promise rejections are deprecated. In the future, promise rejections that are not handled will terminate the Node.js process with a non-zero exit code.
[7104]:WARNING:android/android-emu/android/base/async/AsyncSocketServer.cpp:99:Error when accepting host connectionError message: Unknown error
UpdateLayeredWindowIndirect failed for ptDst=(1002, 87), size=(272x21), dirty=(272x21 0, 0) (The system cannot find message text for message number 0x%1 in the message file for %2.)
此处弹出仿真器,但该应用程序在设备中不可用。我尝试了他在link中描述的方法,但仍然收到此错误。
答案 0 :(得分:0)
由于您的错误消息与其他答案中的错误消息不同,请尝试编辑代码以同时添加您的错误消息。
if ((error && error.message &&
(error.message.indexOf('not found') > -1)) ||
(error.message.indexOf('device offline') > -1) ||
(error.message.indexOf('device still connecting') > -1) ||
(error.message.indexOf('device still authorizing') > -1))