如何查询Mongodb，以使搜索结果处于所需的模式

Question

我想查询mongodb以获得具有所需模式的（按优先级排序）结果，该模式使我得到类型的前两个结果：1和下两个结果类型2和类型3，然后重复

我在数据库中的数据就像

  [
        {"name": "A","priority": 1, "type":1},
        {"name": "B","priority": 1, "type":1},
        {"name": "C","priority": 1, "type":1},
        {"name": "D","priority": 1, "type":1},
        {"name": "E","priority": 1, "type":2},
        {"name": "AA","priority": 1, "type":2},
        {"name": "AB","priority": 1, "type":3},
        {"name": "AAA","priority": 2, "type":1},
        {"name": "BBB","priority": 2, "type":3},
        {"name": "CDD","priority": 2, "type":3},
        {"name": "DE","priority": 1, "type":3},
        {"name": "DEE","priority": 2, "type":3},
        {"name": "EFF","priority": 2, "type":1},
        {"name": "ADA","priority": 2, "type":1},
        {"name": "ABE","priority": 1, "type":2},
        {"name": "ASA","priority": 1, "type":1}

    ]

我想查询mongodb以获得类似

的结果

[
    {"name": "A","priority": 1, "type":1},
    {"name": "B","priority": 1, "type":1},
    {"name": "E","priority": 1, "type":2},
    {"name": "AB","priority": 1, "type":3},
    {"name": "C","priority": 1, "type":1},
    {"name": "DE","priority": 1, "type":1},
    {"name": "AA","priority": 1, "type":2},
    {"name": "DE","priority": 1, "type":3},
    {"name": "D","priority": 1, "type":1},
    {"name": "ABE","priority": 1, "type":2},


    {"name": "AAA","priority": 2, "type":1},
    {"name": "EFF","priority": 2, "type":1},
    {"name": "BBB","priority": 2, "type":3},
    {"name": "ADA","priority": 2, "type":1},
    {"name": "CDD","priority": 2, "type":3},
    {"name": "DEE","priority": 2, "type":3}
]

所以我将最终结果按优先级排序，这样列表的排列是类型1计数2，类型2计数1和类型3计数1，然后重复，如果不存在任何类型项，则移至下一个模式。