Python中的嵌套列表比较

Question

我有2个列表。

list1 = [['vlan 158', '  name MARKE', '  mode vpc'], []]
list2 = [['vlan 158', '  name MARKETING', '  mode vpc'], ['vlan 159', '  name SALES', '  mode vpc']]

list的第一个元素必须匹配，如果匹配则很好，如果不匹配则期望diff作为输出。

预期输出：

+++++++++++++++++ The missing configuration is++++++++++++++

vlan 159
  name SALES
  mode vpc
+++++++++++++++++ The missing configuration is++++++++++++++

我正在尝试以下操作，但不起作用：

print ("+++++++++++++++++ The missing configuration is++++++++++++++\n")
p = [item for index, item in enumerate(list2) if [] != [it for it in item if it not in list1[index]]]
print('\n'.join(['\n'.join(item) for item in p]))
print ("+++++++++++++++++ The missing configuration is++++++++++++++\n")
q = [item for index, item in enumerate(list1) if [] != [it for it in item if it not in list2[index]]]
print('\n'.join(['\n'.join(item) for item in q]))

请建议如何完成？

当前输出：

+++++++++++++++++ The missing configuration is++++++++++++++

vlan 158
  name MARKETING
  mode vpc
vlan 159
  name SALES
  mode vpc
+++++++++++++++++ The missing configuration is++++++++++++++

vlan 158
  name MARKE
  mode vpc