Question

Sybase DBMS

在我的玩家表格中，我有4列：

播放器
得分
post_dt
add_dt

如果我想找到玩家的得分，其中post_dt是最大值，而add_dt是该post_dt和那个玩家的最大值，我该怎么做？我的下面的查询需要很长时间才能运行，而且效率可能不是很高。

select player, score from tb t1 
where post_dt in 
      (select max(add_dt) 
       from tb t2 
       where t1.player = t2.player and t2.post_dt in 
             (select max(post_dt) 
              from tb t2 
              where t1.player = t2.player))

表

PLAYER    SCORE POST_DT      ADD_DT 

001         15  2017-02-01   2017-01-15
001         26  2017-02-01   2017-01-17  
001         31  2017-01-28   2017-01-10
002         4   2017-03-25   2017-02-25  
002         14  2017-03-25   2017-02-13
002         27  2017-03-25   2017-03-05
003         31  2017-01-02   2016-12-25
003         4   2017-01-03   2016-12-25

查询的预期结果：

01, 26, 2017-02-01, 2017-01-17
02, 27, 2017-03-25, 2017-03-05
03,  4, 2017-01-03, 2016-12-25

Answer 1

您可以通过使用相关子查询来实现。

SELECT t1.player,
       t1.score
       FROM tb t1
       WHERE t1.post_dt = (SELECT max(t2.post_dt)
                                  FROM tb t2
                                  WHERE t2.player = t1.player)
             AND t1.add_dt = (SELECT max(t2.add_dt)
                                     FROM tb t2
                                     WHERE t2.player = t1.player
                                           AND t2.post_dt = t1.post_dt);

或者，如果您的DBMS支持窗口功能，则使用rank()窗口功能。

SELECT x.player,
       x.score
       FROM (SELECT t.player,
                    t.score,
                    rank() OVER (PARTITION BY t.player
                                 ORDER BY t.post_dt DESC,
                                          t.add_dt DESC) r
                    FROM tb t) x
       WHERE x.r = 1;

另一个选择是内部联接子查询，它们分别通过player或player和post_dt来构建最大值。

SELECT t1.player,
       t1.score
       FROM tb t1
            INNER JOIN (SELECT t2.player,
                               max(t2.post_dt) post_dt
                               FROM tb t2
                               GROUP BY t2.player) t3
                       ON t3.player = t1.player
                          AND t3.post_dt = t1.post_dt
            INNER JOIN (SELECT t3.player,
                               t3.post_dt,
                               max(t3.add_dt) add_dt
                               FROM tb t3
                               GROUP BY t3.player,
                                        t3.post_dt) t4
                       ON t4.player = t1.player
                          AND t4.post_dt = t1.post_dt
                          AND t4.add_dt = t1.add_dt;

如何找到val1的最大值，其中val2是最大值？

1 个答案: