Question

我有一个AWS Python lambda函数，我想在其中调用另一个lambda函数。我有一个有效的硬编码有效负载，我尝试对其进行重现以使其更适合我的用例。因此，使用相同的数据定义payload_dict。

我还附上了受人尊敬的用法的印刷品作为内联注释，以防万一希望使它成为一个更好的问题。

简而言之，问题是：如何使json.dumps(payload_dict).encode()的行为与lambda_client.invoke中的硬编码版本相同？在Python 3.6上运行

from datetime import datetime, timedelta
import boto3
import sys
import json
import ast

def lambda_handler(event, context):

    startTime = datetime.today() - timedelta(days=0)
    endTime = datetime.today() - timedelta(days=1)

    payload_dict = {}
    payload_dict['instanceID'] = "i-id"
    payload_dict['StartTime'] = startTime.isoformat(' ', 'seconds')
    payload_dict['EndTime'] = endTime.isoformat(' ', 'seconds')

    print("PAYLOAD: ",json.dumps(payload_dict).encode()) # b'{"instanceID": "i-id", "StartTime": "2018-08-03 19:11:32", "EndTime": "2018-08-02 19:11:32"}'

    #actually working payload
     payload=b"""{
       "instanceID": "i-id",
       "StartTime": "2018-08-01 00:00:00",
       "EndTime": "2018-08-02 00:00:00"
      }"""
#b'{"instanceID": "i-id","StartTime": "2018-08-01 00:00:00", "EndTime": "2018-08-02 00:00:00"}'

调用另一个lambda：

invoke_response = lambda_client.invoke(FunctionName="daily_average_cpu_utilisation_lambda",
                                           InvocationType='RequestResponse',
                                           LogType='Tail',
                                           Payload = payload
                                           )

在调用时从lambda_client.invoke获取json.dumps(payload_dict).encode()作为有效载荷的信息时发生的错误 percentage_usage = invoke_response['Payload'].read().decode('utf8').replace("'", '"'）：

Response:
{
  "errorMessage": "Expecting ',' delimiter: line 1 column 289 (char 288)",
  "errorType": "JSONDecodeError",
  "stackTrace": [
    [
      "/var/task/lambda_function.py",
      46,
      "lambda_handler",
      "percentage_dict = json.loads(percentage_usage)"
    ],
    [
      "/var/lang/lib/python3.6/json/__init__.py",
      354,
      "loads",
      "return _default_decoder.decode(s)"
    ],
    [
      "/var/lang/lib/python3.6/json/decoder.py",
      339,
      "decode",
      "obj, end = self.raw_decode(s, idx=_w(s, 0).end())"
    ],
    [
      "/var/lang/lib/python3.6/json/decoder.py",
      355,
      "raw_decode",
      "obj, end = self.scan_once(s, idx)"
    ]
  ]
}

希望这是一个很好的问题，并且非常感谢您的帮助，至少直到现在，我还是看不到或调试过，如何看似相同的负载如何如此不同地解释，也很可能是我错过的显而易见的东西

AWS Lambda Python期待'，'分隔符异常

0 个答案: