我正在尝试将int j=0;
Car car = miniTable.get(i);
content[i][j++]= car.getName();
content[i][j++]= car.getOrigin();
content[i][j++]= car.getColor();
替换为groupByKey()，我是pyspark和python新手，并且很难确定reudceByKey()操作的lambda函数。
这是代码
reduceByKey()这是返回值
dd = hive_context.read.orc(orcfile_dir).rdd.map(lambda x: (x[0],x)).groupByKey(25).take(2)
这是可迭代的内容>>> dd
[(u'KEY_1', <pyspark.resultiterable.ResultIterable object at 0x107be0c50>), (u'KEY_2', <pyspark.resultiterable.ResultIterable object at 0x107be0c10>)]
dd[0][1]我的问题是如何用Row(key=u'KEY_1', hash_fn=u'deec95d65ca6b3b4f2e1ef259040aa79', value=u'e7dc1f2a')
Row(key=u'KEY_1', hash_fn=u'f8891048a9ef8331227b4af080ecd28a', value=u'fb0bc953')
....
...
Row(key=u'KEY_1', hash_fn=u'1b9d2bb2db28603ff21052efcd13f242', value=u'd39714d3')
Row(key=u'KEY_1', hash_fn=u'c41b0269706ac423732a6bab24bf8a6a', value=u'ab58db92')
替换并获得与上述相同的输出？