使用asyncio.wait

Question

我有多个应同时运行的协程，其中一些可能会引发异常。在这种情况下，应重新运行协程。我该如何完成？我正在尝试做的最小演示：

import asyncio
import time

t = time.time()


async def c1():
    print("finished c1 {}".format(time.time() - t))


async def c2():
    await asyncio.sleep(3)
    print("finished c2 {}".format(time.time() - t))


called = False


async def c3():
    global called
    # raises an exception the first time it's called
    if not called:
        called = True
        raise RuntimeError("c3 called the first time")
    print("finished c3 {}".format(time.time() - t))


async def run():
    pending = {c1(), c2(), c3()}

    num_times_called = 0
    while pending:
        num_times_called += 1
        print("{} times called with {} pending tasks: {}".format(num_times_called, len(pending), pending))

        finished, pending = await asyncio.wait(pending, return_when=asyncio.FIRST_EXCEPTION)
        for task in finished:
            if task.exception():
                print("{} got an exception {}, retrying".format(task, task.exception()))
                pending.add(task)

        print("finished {}".format(finished))

    print("finished all {}".format(time.time() - t))


asyncio.get_event_loop().run_until_complete(run())

c3()表示某些协程将失败，需要重新运行。演示的问题是完成的任务已完成并具有异常集，因此当我将其放回挂起的集时，下一个运行循环将立即退出而无需重新运行c3()，因为它已经完成了。

是否有一种方法可以清除任务，使其再次运行c3()？我知道附加到任务的协程实例将无法再等待，否则我会得到

  

RuntimeError('cannot reuse already awaited coroutine',)

这意味着我必须手动管理从协程实例到生成它的协程的映射，然后使用task._coro检索失败的协程实例-是吗？

Answer 1

编辑：任务本身可能是地图中的键，它更简洁。

async def run():
    tasks = {asyncio.ensure_future(c()): c for c in (c1, c2, c3)}
    pending = set(tasks.keys())

    num_times_called = 0
    while pending:
        num_times_called += 1
        print("{} times called with {} pending tasks: {}".format(num_times_called, len(pending), pending))

        finished, pending = await asyncio.wait(pending, return_when=asyncio.FIRST_EXCEPTION)
        for task in finished:
            if task.exception():
                print("{} got an exception {}, retrying".format(task, task.exception()))
                coro = tasks[task]
                new_task = asyncio.ensure_future(coro())
                tasks[new_task] = coro
                pending.add(new_task)

        print("finished {}".format(finished))

    print("finished all {}".format(time.time() - t))