Question

我们的映射超级类创建了byBy列，该列定义为延迟加载

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        self.tableview.reloadData()
    })

我需要在继承了上述类的子类之一中热切加载此属性。

@MappedSuperclass
@EntityListeners(AuditingEntityListener.class)
@XmlAccessorType(XmlAccessType.FIELD)
public abstract class AbstractAuditingEntity implements Serializable {
    @CreatedBy
    @ManyToOne(fetch = FetchType.LAZY)
    @XmlTransient
    @JoinColumn(name = "created_by", updatable = false, columnDefinition = "bigint")
    protected User createdBy;

   public User getCreatedBy() {
      return createdBy;
   }

   public void setCreatedBy(User createdBy) {
      this.createdBy = createdBy;
   }

我该怎么做？

我尝试了以下操作（使用了NamedEntityGraph和HQL），但是都没有从定义为延迟的MappedSuperClass返回createdBy

@Override
@XmlElement(name = "createdBy")
@JsonProperty("createdBy")
public User getCreatedBy() {
    return super.getCreatedBy();
}

---使用HQL FETCH JOIN-

//defined at the top of Model
@NamedEntityGraphs({
        // eagerly fetches created by and program names when used
        @NamedEntityGraph(
                name = "graphWithCreatedBy",
                attributeNodes = {
                        @NamedAttributeNode("createdBy")
                }
        )
})

//Repository method
@EntityGraph(value = "Program.createdBy", type = EntityGraph.EntityGraphType.FETCH) //tried both LOAD and FETCH
    Program findOne(Specification<Program> specification);

这两种方法均返回程序，但不能返回createdBy用户我究竟做错了什么？

Mapped Super类中的渴望获取属性

0 个答案: