Question

我有一个问题：我有这个数据库：

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| Germany         | Italy               | Belgium              |
-----------------------------------------------------------------
| Gerhard Richter | Leonardo da Vinci   | Anton van Dyck       |
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| Paul Klee       | Sandro Botticelli   | Michaël Borremans    |
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| Neo Rauch       | Masaccio            | Paul Delvaux         |
-----------------------------------------------------------------

我想在一行中为每一行而不是每一列添加一个值：

此处图片：https://puu.sh/B81Po/03395bad74.png

我添加了.split(", ");，但现在将每一行分为3行，这很好，但是我也需要添加其他列值。

代码：

const Obj = {
    "0":"Neo Rauch, Paul Klee, Gerhard Richter",
    "1":"Masaccio, Sandro Botticelli, Leonardo da Vinci",
    "2":"Paul Delvaux, Michaël Borremans, Anton van Dyck"  
};

const Obj2 = {}
Object.keys(Obj).forEach(function(key) {
  Obj2[key] = Obj[key].split(", ");
});

console.log(Obj2);

编辑：现在怎么样：

"0":"Neo Rauch, Paul Klee, Gerhard Richter",
"1":"Masaccio, Sandro Botticelli, Leonardo da Vinci",
"2":"Paul Delvaux, Michaël Borremans, Anton van Dyck"

我想要什么：

"0":"Neo Rauch", "Masaccio", "Paul Delvaux"
"1":"Paul Klee", "Sandro Botticelli", "Michaël Borremans"
"2":"Gerhard Richter", "Leonardo da Vinci", "Anton van Dyck"

Answer 1

您可以使用“，”将数组连接起来，以便在每个单词周围加上双引号。希望这就是你想要的。

const Obj = {
    "0":"Neo Rauch, Paul Klee, Gerhard Richter",
    "1":"Masaccio, Sandro Botticelli, Leonardo da Vinci",
    "2":"Paul Delvaux, Michaël Borremans, Anton van Dyck"  
};

const Obj2 = {}
Object.keys(Obj).forEach(function(key) {
  Obj2[key] = Obj[key].split(", ").join('","');
});

console.log(Obj2);

Answer 2

您想要的不是格式正确的对象，这将导致语法错误。这是一种获得我认为是您想要的结果的方法。

第一个控制台是嵌套对象，第二个是具有嵌套数组的对象。

const Obj = {
    "0":"Neo Rauch, Paul Klee, Gerhard Richter",
    "1":"Masaccio, Sandro Botticelli, Leonardo da Vinci",
    "2":"Paul Delvaux, Michaël Borremans, Anton van Dyck"  
};

const Obj2 = {};
const Obj3 = {};

Object.keys(Obj).forEach(function(key) {
    var string = [];
    Object.keys(Obj).forEach(function(k) {
    	string.push(Obj[k].split(", ")[key]);
    });

    var obj = string.reduce(function(acc, cur, i) {
        acc[i] = cur;
        return acc;
    }, {});

    Obj2[key] = obj;
    Obj3[key] = string;
});

console.log(Obj2);
console.log(Obj3);

如何分裂和融合？

2 个答案: