Question

我正四处乱逛，想看看我能否使这个简单的程序正常工作。我想对照我的列表检查用户输入，并输出它是否在列表中。我目前如何设置它，它将返回0索引，但不返回其他两个索引。我在做什么错了？

print("Check to See if You are Registered:")
name = input("Please Enter Your Name:")
check_name = ["lisa", "jim", "betty"]

if name == check_name[0]:
   print("Welcome lisa")

   if name == check_name[1]:
      print("Welcome jim")

   elif name == check_name[2]:
        print("Welcome betty")

   pass

else:
    print("Sorry, Looks like you are not in the system")

pass

Answer 1

您的最后两个if语句仅对嵌套在第一个语句中的值进行求值。您需要取消缩进，以便他们可以评估是否第一个不匹配。

另一种解决方案：

print("Check to See if You are Registered:")
name = input("Please Enter Your Name:")
check_name = ["lisa", "jim", "betty"]
if name not in check_name:
    print("Sorry, Looks like you are not in the system")

Answer 2

您有缩进问题。

print("Check to See if You are Registered:")
name = input("Please Enter Your Name:")
check_name = ["lisa", "jim", "betty"]

if name == check_name[0]:
    print("Welcome lisa")

elif name == check_name[1]:
    print("Welcome Jim")

elif name == check_name[2]:
    print("Welcome Betty")

else:
    print("Sorry, Looks like you are not in the system")

Answer 3

您已经在上面得到答案。这是另一种解决方案，无需使用多个if语句来简化代码：

print("Check to See if You are Registered:")
name = input("Please Enter Your Name:")
check_name = ["lisa", "jim", "betty"]

if name in check_name:
    print("Welcome %s" %name)
else:
    print("Sorry, Looks like you are not in the system")

命令if name in check_name:检查输入的名称是否在名称列表中，并欢迎相应的人。如果输入名称不存在，则会引发Sorry...语句

Python的新手，需要一些指导以对照列表检查用户输入

3 个答案: