Question

具有一个只有一列的数据帧，并且每行都要检查一下这些数据中是否包含“＃”：

"https://example.com/test-ability/321#321"
"https://example.com/test-ability/"
"anothertext#"
"notwithwhatyousearch"

如何查找每行是否包含字符“＃”并创建第二个新列，并将具有此字符的行标记为“ A”，将没有此字符的行标记为“ B”？预期结果示例

"https://example.com/test-ability/321#321", "A"
    "https://example.com/test-ability/", "B"
    "anothertext#", "A"
    "notwithwhatyousearch", "B"

Answer 1

th:checked="${1 == 1}"/>

或基本的R解决方案：

df = data.frame(x = c("https://example.com/test-ability/321#321",
                      "https://example.com/test-ability/",
                      "anothertext#",
                      "notwithwhatyousearch"), stringsAsFactors = F)

library(dplyr)

df %>% mutate(flag = ifelse(grepl("#", x), "A", "B"))

#                                          x flag
# 1 https://example.com/test-ability/321#321    A
# 2        https://example.com/test-ability/    B
# 3                             anothertext#    A
# 4                     notwithwhatyousearch    B

Answer 2

尝试使用此Python代码，我对R语言了解不多，可能会为您提供参考：

ls=["https://example.com/test-ability/321#321",
"https://example.com/test-ability/",
"anothertext#",
"notwithwhatyousearch"]          #Creating Data Frame

length=len(ls)                   #Finding list length
for i in range(0, length):       #Iteration
    if('#' in ls[i]):
        print(ls[i],' A')
    else:
        print(ls[i],' B')

查找行是否包含字符并创建新列以标记数据

2 个答案: