Question

很难解释为标题。我正在这里下载文件并使用进度条的修改版本：https://gist.github.com/somada141/b3c21f7462b7f237e522

我只想显示诸如10％--- 20％---等增量，但是代码已调整为显示小数位，这意味着默认输出将为10.12％10.45％10.67％10.89％。

因此，即使我执行if语句并与10匹配，由于上述所有匹配都等于10，我最终还是要进行10％的打印4次。

完整代码

response = urllib2.urlopen(url)
with open("myfile.zip", "wb") as local_file:
     local_file.write(self.chunk_read(response, report_hook=self.chunk_report))

def chunk_report(self, bytes_so_far, chunk_size, total_size):
    percent = round(float(bytes_so_far) / total_size * 100))

    if percent == 10:
        print("%0.0f%%\r" % (percent))
    elif percent == 20:
        print("%0.0f%%\r" % (percent))
    elif percent == 30:
        print("%0.0f%%\r" % (percent))

    if bytes_so_far >= total_size:
        sys.stdout.write('\n')

def chunk_read(self, response, chunk_size=8192, report_hook=None):
    total_size = response.info().getheader('Content-Length').strip()
    total_size = int(total_size)
    bytes_so_far = 0
    data = []

    while 1:
        chunk = response.read(chunk_size)
        bytes_so_far += len(chunk)

        if not chunk:
            break

        data += chunk
        if report_hook:
            report_hook(bytes_so_far, chunk_size, total_size)

    return "".join(data)

这给出了输出：

10%
10%
10%
10%
20%
20%
20%
20%

我希望只打印10％，一次只打印20％。

编辑：根据joaquin的回答，完全有效的代码如下：

response = urllib2.urlopen(url)
with open("myfile.zip", "wb") as local_file:
 local_file.write(self.chunk_read(response, report_hook=self.chunk_report))


def chunk_report(self, bytes_so_far, chunk_size, total_size, status):
    percent = float(bytes_so_far) / total_size
    percent = round(percent*100)
    if percent >= status:
        print("%0.0f%%\r" % (percent))
        status += 10
    return status

    if bytes_so_far >= total_size:
        print('\n')


def chunk_read(self, response, chunk_size=8192, report_hook=None):
    total_size = response.info().getheader('Content-Length').strip()
    total_size = int(total_size)
    bytes_so_far = 0
    data = []
    status = 0

    while 1:
        chunk = response.read(chunk_size)
        bytes_so_far += len(chunk)

        if not chunk:
            break

        data += chunk
        if report_hook:
            status = report_hook(bytes_so_far, chunk_size, total_size, status)

    return "".join(data)

Answer 1

这里有一个示例，该示例可以产生10％.... 100％的内容，而无需使用if系列

target_percent = 10
total_size = 1000
for bytes_so_far in range(1, 1000):
    percent = float(bytes_so_far) / total_size
    percent = round(percent*100)

    if percent >= target_percent:
        print("%0.0f%%\r" % (percent))
        target_percent += 10

您得到：

10%
20%
30%
40%
50%
60%
70%
80%
90%
100%

这可以在函数内部进行组织：

def get_percent(bytes_so_far, total_size, status):
    percent = float(bytes_so_far) / total_size
    percent = round(percent*100)

    if percent >= status:
        print("%0.0f%%\r" % (percent))
        status += 10
    return status

如果我们模拟对该函数的重复调用：

size = 1000
status = 10
for bytes_so_far in range(1, 1000):
    status = get_percent(bytes_so_far, size, status)

我们再次得到：

10%
20%
30%
40%
50%
60%
70%
80%
90%
100%

如果在Python中将打印输出限制为每个小数点后1条语句

1 个答案: