这是我的代码,获取我需要的查询结果
$json_array = array();
$sql = "call rep_info();";
$result = $connect->query($sql);
while ($row = $result->fetch_assoc()) {
$json_array[] = $row;
}
mysqli_free_result($result);
mysqli_next_result($connect);
// Buat info user
$json_array2 = array();
$sql = "call rep_user();";
$result = $connect->query($sql);
while ($row = $result->fetch_assoc()) {
$json_array2[]["user"] = $row;
}
然后我像这样将两个数组合并为一个
$timeline = array_merge($json_array[0],$json_array2[0]);
$timeline2 = array_merge($json_array[1],$json_array2[1]);
$timeline = array_merge($timeline,$timeline2);
编码合并后的数组以及回显变量
$encoded = json_encode($timeline);
echo $encoded;
所以基本上我想要显示的是查询结果的两行,它们来自json_array [0]和json_array [1]。但是我在json_array [1]和json_array2 [1]的回显结果中只得到1行。
这段代码有什么问题?谢谢!
编辑:
print_r($json_array[0]);
print_r($json_array2[0]);
Array
(
[id] => 11087
[message] => Late post.\nDarmo ramai lancar
[latitude] => -7.292500019073486
[longitude] => 112.7388916015625
[image] => 1529894809620.jpeg
[thumb] =>
[sub_category] =>
[is_need_respond] => 0
[is_sticky] => 0
[is_hidden] => 0
[viewed] => 18
[deleted_at] =>
[created_at] => 2018-06-25 02:48:04
)
Array
(
[user] => Array
(
[id] => 621
[name] => asd
[username] => asd
[verified] => 2
[avatar] => icfab.jpg
[level] => 10
)
)
答案 0 :(得分:0)
尝试这样
$timeline = $json_array[0];
$timeline['user'] = $json_array2[0]['user'];
$timeline2 = $json_array[1];
$timeline2['user'] = $json_array2[1]['user'];
$timeline = [$timeline, $timeline2];
$encoded = json_encode($timeline);
echo $encoded;
假设$json_array
与$json_array2
的长度相同,则可以像这样合并它们
foreach($json_array as $idx => &$item)
{
$item['user'] = &$json_array2[$idx]['user'];
}
echo json_encode($json_array);
我不确定您为什么不理解这个1行周期。我会尽力解释它。
您有两个长度相同的数组-$json_array
和$json_array2
。
您遍历$json_array
中的每个元素,并查看$json_array2
中相同的数组索引。当两个数组中都有对应的元素时,只需将第二个数组中的user
键复制到第一个数组中即可。