Question

如何在python 2.4上对以下日期数组进行排序

 timestamps = ['2011-06-2', '2011-08-05', '2011-02-04', '2010-1-14', '2010-12-13', '2010-1-12', '2010-2-11', '2010-2-07', '2010-12-02', '2011-11-30', '2010-11-26', '2010-11-23', '2010-11-22', '2010-11-16']

Answer 1

>>> import datetime
>>> dates = [datetime.datetime.strptime(ts, "%Y-%m-%d") for ts in timestamps]
>>> dates.sort()
>>> sorteddates = [datetime.datetime.strftime(ts, "%Y-%m-%d") for ts in dates]
>>> sorteddates
['2010-01-12', '2010-01-14', '2010-02-07', '2010-02-11', '2010-11-16', '2010-11-
22', '2010-11-23', '2010-11-26', '2010-12-02', '2010-12-13', '2011-02-04', '2011
-06-02', '2011-08-05', '2011-11-30']

Answer 2

sorted(timestamps, key=lambda d: map(int, d.split('-')))

Answer 3

>>> import time
>>> timestamps = ['2011-06-2', '2011-08-05', '2011-02-04', '2010-1-14', '2010-12-13', '2010-1-12', '2010-2-11', '2010-2-07', '2010-12-02', '2011-11-30', '2010-11-26', '2010-11-23', '2010-11-22', '2010-11-16']
>>> timestamps.sort(key=lambda x: time.mktime(time.strptime(x,"%Y-%m-%d")))
>>> timestamps
['2010-1-12', '2010-1-14', '2010-2-07', '2010-2-11', '2010-11-16', '2010-11-22', '2010-11-23', '2010-11-26', '2010-12-02', '2010-12-13', '2011-02-04', '2011-06-2', '2011-08-05', '2011-11-30']

Answer 4

这样做：

timestamps.sort()

结果：

['2010-1-12',
 '2010-1-14',
 '2010-11-16',
 '2010-11-22',
 '2010-11-23',
 '2010-11-26',
 '2010-12-02',
 '2010-12-13',
 '2010-2-07',
 '2010-2-11',
 '2011-02-04',
 '2011-06-2',
 '2011-08-05',
 '2011-11-30']

订单年 - 月 - 日允许进行这样的排序，因为一个月之前的一天变化，一个月在时间过去的一年之前发生变化。

就像一个数字：统一数字（最右边的数字）在十位数之前改变，后者在百位数之前改变，当逐渐增加1时。

事实上 sort（）从左到右处理：如果一个精确位置的字符在两个字符串中相同以进行排序，它将检查两个字符中的两个字符在以下位置的字符串，以决定哪一个在逻辑上先于。

此外'0'＆lt; '1'是 True ，'1'＆lt; '2'是 True 等

Answer 5

map(lambda x:x[1], sorted(map(lambda a:[map(int,a.split('-')),a], timestamps)))

['2010-1-12',
 '2010-1-14',
 '2010-2-07',
 '2010-2-11',
 '2010-11-16',
 '2010-11-22',
 '2010-11-23',
 '2010-11-26',
 '2010-12-02',
 '2010-12-13',
 '2011-02-04',
 '2011-06-2',
 '2011-08-05',
 '2011-11-30']

Answer 6

print(sorted(list_of_strings,key=lambda x :(int(x.split('-')[0]),int(x.split('-')[1]),int(x.split('-')[2])))

Answer 7

如果您将它们分类为相同的格式，则只需拨打timestamps.sort()

即可

Answer 8

这种升序日期为dd / mm / yyyy格式

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Answer 9

在Python 3中并使用（我个人最喜欢的）理解。对于日期，我将始终使用Python的+----------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------+---+ |plan |tag| +----------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------+---+ |== Physical Plan == *(1) Project [unique_id#27L] +- *(1) Filter (true = (exists#53 && exists#54)) +- *(1) BroadcastHashJoin [country#22], [country#3], ExistenceJoin(exists#54), BuildRight :- *(1) BroadcastHashJoin [country#22], [country#8], ExistenceJoin(exists#53), BuildRight : :- *(1) Project [country#22, unique_id#27L] : : +- *(1) Filter isnotnull(EMAIL#20) : : +- LocalTableScan [name#19, email#20, phone#21, country#22, unique_id#27L] : +- BroadcastExchange HashedRelationBroadcastMode(List(input[0, string, true])) : +- LocalTableScan [country#8] +- BroadcastExchange HashedRelationBroadcastMode(List(input[0, string, true])) +- LocalTableScan [country#3]|big| +----------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------+---+ lib：

datetime

在python数组中排序日期

9 个答案: