我有一个帐户表单,其中所有帐户都从mysql数据库中拉到下拉菜单中。用户从下拉菜单中选择帐户,然后通过data-acc属性自动填充帐户代码字段。我添加了一个按钮以添加更多帐户。
它适用于第一组输入和选择框,但不适用于下一组输入和选择框
示例屏幕截图
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.2.0/jquery.min.js"></script>
<script>
$('select[name="account_name[]').change(function()
{
$('.account_num').val($('select[name="account_name[]"] option:selected').data('acc'));
});
</script>
<script>
$(document).ready(function(){
var i=1;
var chart_add = '<tr id="row_chart'+i+'"><td align="center"> <input type="text" name="account_code[]" class="form-control account_num" readonly></td><td><select class="form-control selectpicker" data-live-search="true" name="account_name[]" required> <option></option><?php $account = mysqli_query($conn,"SELECT chart_of_account.acoount_no, chart_of_account.account_title from chart_of_account inner join account_group_tbl on chart_of_account.account_group = account_group_tbl.account_name where account_group_tbl.account_type = 'Expense'");while($acc = mysqli_fetch_assoc($account)){$account_no = $acc['acoount_no'];$account_title = $acc['account_title'];?><option value="<?php echo $account_title; ?>" data-price="<?php echo $account_no; ?>"><?php echo $account_title ; ?> </option><?php } ?></select></td><td><button type="button" name="remove_chart" id="'+i+'" class="btn btn-danger remove_chart"><i class="fa fa-minus"></i></button></td></tr>';
$('#add').click(function(){
i++;
$('#dynamic_field').append(chart_add);
$('.selectpicker').selectpicker('render');
});
$(document).on('click', '.remove_chart', function(){
var button_id = $(this).attr("id");
$('#row_chart'+button_id+'').remove();
});
});
</script>
<div class="row">
<div class="col-md-12">
<div class="box box-default">
<div class="box-header with-border">
<h3 class="box-title">Report Per Office</h3>
</div>
<div class="box-body">
<div class="col-md-12">
<h4>Project Procurement Management Plan (PPMP) <hr >
</div>
<div class="col-md-1">
Office:
</div>
<div class="col-md-4">
<select class="selectpicker" data-live-search="true" name="office_from" data-width="auto" required >
<option>--Select Reponsible Office--</option>
<?php
$q = "SELECT * FROM `office_code_dept`";
$r = mysqli_query($conn,$q);
while($row = mysqli_fetch_assoc($r)){
$off_desc = $row['off_name'];
?>
<option value="<?php echo $off_desc;?>"><?php echo $off_desc; ?></option>
<?php
}
?>
</select>
</div>
<div class="col-md-1">Year:</div>
<div class="col-md-4"><input type="number" min="1990" max="3000" name="tax_year" class="form-control" style="text-align: center;" value="<?php echo date('Y'); ?>"></div>
<div class="col-md-2"><input type="submit" name="search" value="Search" class="btn btn-primary btn-block">
</div>
<div class="col-md-12"><br></div>
</h4>
<table class="table table-bordered" id="dynamic_field">
<thead>
<tr>
<th width="7%" rowspan="2" style="text-align: center;">Code</th>
<th width="27%" rowspan="2" style="text-align: center;">General Description</th>
<th rowspan="2" width="5%"><button type="button" name="add" id="add" class="btn btn-success"><i class="fa fa-plus"></i></button></th>
</tr>
</thead>
<tbody>
<tr>
<td align="center">
<input type="text" name="account_code[]" class="form-control account_num" readonly>
</td>
<td>
<select class="form-control selectpicker" data-live-search="true" name="account_name[]" required>
<option></option>
<?php
$account = mysqli_query($conn,"SELECT chart_of_account.acoount_no, chart_of_account.account_title from chart_of_account inner join account_group_tbl on chart_of_account.account_group = account_group_tbl.account_name where account_group_tbl.account_type = 'Expense'");
while($acc = mysqli_fetch_assoc($account)){
$account_no = $acc['acoount_no'];
$account_title = $acc['account_title'];
?>
<option value="<?php echo $account_title; ?>" data-acc="<?php echo $account_no; ?>">
<?php echo $account_title ; ?>
</option>
<?php } ?>
</select>
</td>
<td></td>
</tr>
</tbody>
</table>
</div>
</div>
</div>
</div>
答案 0 :(得分:0)
您的.change函数未绑定到新输入并选择框
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.2.0/jquery.min.js"></script>
<script>
$('select[name="account_name[]').change(function()
{
$('.account_num').val($('select[name="account_name[]"] option:selected').data('acc'));
});
</script>
<script>
$(document).ready(function(){
var i=1;
var chart_add = '<tr id="row_chart'+i+'"><td align="center"> <input type="text" name="account_code[]" class="form-control account_num" readonly></td><td><select class="form-control selectpicker" data-live-search="true" name="account_name[]" required> <option></option><?php $account = mysqli_query($conn,"SELECT chart_of_account.acoount_no, chart_of_account.account_title from chart_of_account inner join account_group_tbl on chart_of_account.account_group = account_group_tbl.account_name where account_group_tbl.account_type = 'Expense'");while($acc = mysqli_fetch_assoc($account)){$account_no = $acc['acoount_no'];$account_title = $acc['account_title'];?><option value="<?php echo $account_title; ?>" data-price="<?php echo $account_no; ?>"><?php echo $account_title ; ?> </option><?php } ?></select></td><td><button type="button" name="remove_chart" id="'+i+'" class="btn btn-danger remove_chart"><i class="fa fa-minus"></i></button></td></tr>';
$('#add').click(function(){
i++;
$('#dynamic_field').append(chart_add);
$('.selectpicker').selectpicker('render');
$('select[name="account_name[]').change(function()
{
$('.account_num').val($('select[name="account_name[]"] option:selected').data('acc'));
});
});
$(document).on('click', '.remove_chart', function(){
var button_id = $(this).attr("id");
$('#row_chart'+button_id+'').remove();
});
});
</script>
类似的事情应该起作用。