Question

当前，我的结果集是由该语句定义的

 ISNULL('| ' + [Contry],'') + ISNULL('| ' + [State],'') + ISNULL('| ' + [City],'')   
 AS ProjectLocation

上面显示的“位置”文件的当前输出如下所示：

United States, United States, United States| California, Hawaii, Virginia| Norfolk, Pearl Harbor, San Diego,

我需要输出如下：

United States,  Hawaii,  Pearl Harbor |  United States,  Virginia, Norfolk |  United States, California,  San Diego

上面调用的列的值是根据FOR XML PATH('')函数定义的，如下所示：

WITH CTE AS 
(
    SELECT 
        (SELECT Country.CountryName  + ', '
         FROM MyDB.dbo.Country c
         INNER JOIN MyDB.dbo.Contract con ON c.CountryID = con.ContryID 
                                          AND Opp.OppID = Con.OppID 
         FOR XML PATH('')) AS Country,  
        (SELECT State.StateName + ', ' 
         FROM MyDB.dbo.State s
         INNER JOIN MyDB.dbo.Contract con ON s.StateID = con.ContryID 
                                          AND Opp.OppID = Con.OppID 
         FOR XML PATH('')) AS State, 
        (SELECT State.StateAbbr  + ', ' 
         FROM MyDB.dbo.State s
         INNER JOIN MyDB.dbo.Contract con ON s.StateID = con.ContryID 
                                          AND Opp.OppID = Con.OppID 
         FOR XML PATH('')) AS StateCode, 
        (SELECT Location.LocationName  + ', ' 
         FROM MyDB.dbo.Location l
         INNER JOIN MyDB.dbo.Contract con ON l.LocationID= con.LocationID
                                          AND Opp.OppID = Con.OppID 
         FOR XML PATH('')) AS City
    FROM         ''"
        YourDB.dbo.Opportunity Opp
)
SELECT ...
FROM CTE

P.S。

“ YourDB.dbo.Opportunity”表代表一个表，其中包含可用于承包商的所有项目

“ MyDB.dbo.Contract”表是一个查找表，用于将项目与雇用的承包商联系起来。

所以这就是为什么我需要调用FOR XML Function作为一个机会的原因，可能有多个承包商位于不同的州和城市。

当前，我使用非常冷杉的语句从CTE中进行选择，如下所示：

SELECT
  ISNULL('| ' + [Contry],'') + ISNULL('| ' + [State],'') + ISNULL('| ' + [City],'')   
 AS ProjectLocation
FROM CTE

但是正如我所说，它产生了错误的输出。

Answer 1

因此，您在一个表中有一个完整的地址。这是我期望您提供的设置：

declare @Country table (Id int, Name varchar(100));
declare @State table (Id int, Name varchar(100));
declare @Location table (Id int, Name varchar(100));

declare @Opp table (
    Id int,
    CountryId int,
    StateId int,
    LocationId int,
    OpportunityDescription varchar(100)
);

在这样的架构上，您需要将所有位置表连接在一起，将它们的字段组合为一个输出：

select op.*, (
    select concat(c.Name, s.Name, l.Name) as [data()]
    from @Opp p
        inner join @Country c on c.Id = p.CountryId
        inner join @State s on s.Id = p.StateId
        inner join @Location l on l.Id = p.LocationId
    where p.Id = op.Id
    for xml path('')
    ) as [OpportunityLocation]
from @Opp op;

Answer 2

以下代码可以很好地满足您的要求。我建议您维护一个称为“地理”的表，而不是单独的国家/地区，位置表。单个地理位置表将使其更易于维护。由于单个城市的名称可以来自不同的州，国家/地区。例如。贝尔维尤城市名称在美国许多州都有。

CREATE TABLE #Opportunity(OpportunityId int)

INSERT INTO #Opportunity values(1);

CREATE TABLE #Contract(ContractID int, OpportunityID int, CountryId int, StateId int, locationId int )

INSERT INTO #Contract values(1,1,1,1,1),(2,1,1,2,2);

CREATE TABLE #Country(CountryId int, CountryName VARCHAR(10))

INSERT INTO #Country values (1,'USA');

CREATE TABLE #State(StateId int, StateName VARCHAR(10))

INSERT INTO #State values (1,'California'),(2,'Washington');


CREATE TABLE #Location(LocationId int, LocationName VARCHAR(10))

INSERT INTO #Location values (1,'LosAngeles'),(2,'Bellevue');

SELECT c.OpportunityId, c.ContractId, STUFF( (SELECT ','+ CONCAT(CountryName,',',statename,',',locationName)
FROM #Country AS cn
left JOIN #State as s
ON c.StateId = s.StateId
left JOIN #Location AS l
ON c.LocationId = l.LocationId
WHERE c.CountryId = cn.CountryId),1,1,'')
FROM #Contract As c

FOR XML PATH列-将每个值的每次连续出现连接到另一个FOR XML PATH字段

2 个答案: