Question

有一个仅标头的C ++库。当我使用write_basic_package_version_file()时，创建... ConfigVersion.cmake文件，不仅检查版本，而且检查32/64位兼容性：

# if the installed or the using project don't
# have CMAKE_SIZEOF_VOID_P set, ignore it:
if("${CMAKE_SIZEOF_VOID_P}" STREQUAL "" OR "8" STREQUAL "")
   return()
endif()

# check that the installed version has the 
# same 32/64bit-ness as the one which is currently searching:
if(NOT CMAKE_SIZEOF_VOID_P STREQUAL "8")
  math(EXPR installedBits "8 * 8")
  set(PACKAGE_VERSION "${PACKAGE_VERSION} (${installedBits}bit)")
  set(PACKAGE_VERSION_UNSUITABLE TRUE)
endif()

这对于仅标头的lib没有任何意义。我可以手动删除该代码，但是有一种绝妙的方法不生成此“添加”吗？

Answer 1

如果您在调用CMAKE_SIZEOF_VOID_P之前将变量write_basic_package_version_file()设置为未设置（或设置为空字符串），这将确保禁用对位的检查。

实际上，以下所有BasicConfigVersion-*.in模板上都使用了以下代码段：

# if the installed or the using project don't have CMAKE_SIZEOF_VOID_P set, ignore it:
if("${CMAKE_SIZEOF_VOID_P}" STREQUAL "" OR "@CMAKE_SIZEOF_VOID_P@" STREQUAL "")
    return()
endif()

将配置为

if("${CMAKE_SIZEOF_VOID_P}" STREQUAL "" OR "" STREQUAL "")
    return()
endif()

总是返回。

如何跳过xxxConfigVersion.cmake中的32 / 64bit-ness检查

1 个答案: