Question

from sys import exit
def gold_room():
    print ("how much gold you need)")
    amount = int(input("amount:"))
    if 0 in amount or  1 in amount:
        print(amount)
gold_room()

输出

how much gold you need)
amount:1
 line 8, in gold_room
    if 0 in amount or  1 in amount:
TypeError: argument of type 'int' is not iterable

Process finished with exit code 1

为什么会出现此错误？

Answer 1

正如其他人提到的那样，您不清楚要做什么。如果您想打印amount等于1或0，则可以使用此

from sys import exit
def gold_room():
    print ("how much gold you need)")
    amount = int(input("amount:"))
    if 0 == amount or  1 == amount:
        print(amount)
gold_room()

或者如果您要打印数字中的数字是1还是0（即123、220），则可以使用此

from sys import exit
def gold_room():
    print ("how much gold you need)")
    amount = input("amount:")
    if '0' in amount or  '1' in amount:
        print(amount)
gold_room()

Python：出现错误：TypeError：类型'int'的参数不可迭代

1 个答案: