Question

找不到适合我需要的答案，
事实上，我有一个实体类别，它与自己的关系为 One-To-Many, Self-referencing
我需要生成一个名为
的多维度命名值数组样本数组：

Array
(
    [Disaster] => Disaster
    [Disaster_sub] => Array
        (
            [Natural] => Natural
            [War] => War
        )

    [Techno] => Techno
    [Tecno_sub] => Array
        (
            [IT] => IT
            [IT_sub] => Array
            (
                 [Dev] => Dev
                 [Bizz] => Bizz
            )
        )

)

我实际上尝试过的是

public function generateCategoryTree($entity, $arr = [])
{
            $children = $entity->getChildren();
            $parent = $entity->getParent();
            $name = $entity->getName();

            if(is_null($parent)) {
                $parentName = $entity->getName();
                $arr[$parentName] = $parentName;
            }

            if(!is_null($children)) {
                foreach ($children as $child) {
                    $list[$name] = [$name => $name];
                    $this->generateCategoryTree($child, $arr);
                }
            }

        return $arr;
}

然后在另一个函数中调用它，

$queryCategory = $this->entityManager->createQueryBuilder('c')
                    ->select('c')
                    ->from('CategoryBundle:Category', 'c')
                    ->where('c.parent IS NULL')
                    ->orderBy('c.root, c.lft',  'ASC');

        $entities = $queryCategory->getQuery()->getResult();

        $choices = [];

        foreach ($entities as $key => $entity) {
             $choices += $this->generateCategoryTree($entity, $choices));
       }

我就在附近但没有实现，有帮助吗？

Answer 1

我已经解决了它，对于那些遇到相同问题的人，
这是工作代码
注意： 这里的实体类别具有根据Gedmo DoctrineExtensions

的属性和获取方法

public function generateCategoryTree($entity, &$arr = [])
{
    $children = $entity->getChildren();
    $name = $entity->getName();
    $arr += [(string)$entity => $entity->getId()];

    if(count($children) > 0) {
        $arr[$name.'_sub'] = [];
        foreach($children as $child) {
            $this->generateCategoryTree($child, $arr[$name.'_sub']);
        } 
    } 

    return $arr;
}

然后我在这里调用此函数，

$choices = [];

    foreach ($entities as $key => $entity) {
        $this->generateCategoryTree($entity, $choices);
    }

递归函数，用于从OneToMany类别实体的Doctrine数据库结果生成多维数组

1 个答案: