Question

我一直在浏览QT文档，以找到一种在加载页面并发出请求后从QWebEngineView返回http状态代码的方法。我知道QWebEngineView不会与QNetWorkAccessManager交互，这将使完成此工作变得轻而易举。那么，还有其他方法可以使用QWebEngineView从请求中获取HTTP状态代码吗？我尝试了多种方法，包括RequestInterceptor。下面是我尝试使用RequestInterceptor的摘要，但是没有提供实际的HTTP状态代码，而只是给我恒定的值，这是我不想要的。

 /*************requestinterceptor.h**************/
#ifndef REQUESTINTERCEPTOR_H
#define REQUESTINTERCEPTOR_H

#include <QWebEngineUrlRequestInterceptor>
#include <QWebEngineUrlRequestInfo>
#include <QDebug>
#include <QUrl>

class RequestInterceptor : public QWebEngineUrlRequestInterceptor
{
      public:
      explicit RequestInterceptor(QObject * parent = Q_NULLPTR);
       virtual void interceptRequest(QWebEngineUrlRequestInfo & info) Q_DECL_OVERRIDE;
};
  #endif // REQUESTINTERCEPTOR_H

/*************requestinterceptor.cpp***************/

  #include "requestinterceptor.h"

  RequestInterceptor::RequestInterceptor(QObject * parent)
 :QWebEngineUrlRequestInterceptor(parent){}

 void RequestInterceptor::interceptRequest(QWebEngineUrlRequestInfo & info)
  {
  QString rsrct = "";
 switch(info.resourceType())
  {
      case 1:rsrct="ResourceTypeSubFrame, --> frame or iframe";break;
      case 2:rsrct="ResourceTypeStylesheet, --> a CSS stylesheet";break;
      case 3:rsrct="ResourceTypeScript, --> an external script";break;
      case 4:rsrct="ResourceTypeImage, --> an image (jpg/gif/png/etc)";break;
      case 5:rsrct="ResourceTypeFontResource, --> a font";break;
      case 6:rsrct="ResourceTypeSubResource, --> an other subresource.";break;
      case 7:rsrct="ResourceTypeObject, --> an object (or embed) tag for a plugin,";break;
      case 8:rsrct="ResourceTypeMedia, --> a media resource.";break;
      case 9:rsrct="ResourceTypeWorker, --> the main resource of a dedicated worker.";break;
      case 10:rsrct="ResourceTypeSharedWorker, --> the main resource of a shared worker.";break;
      case 11:rsrct="ResourceTypePrefetch, --> an explicitly requested prefetch";break;
      case 12:rsrct="ResourceTypeFavicon, --> a favicon";break;
      case 13:rsrct="ResourceTypeXhr, --> a XMLHttpRequest";break;
      case 14:rsrct="ResourceTypePing, --> a ping request for <a ping>";break;
      case 15:rsrct="ResourceTypeServiceWorker, --> the main resource of a service worker.";break;
  case 16:rsrct="ResourceTypeUnknown";break;

  default : rsrct="Unknown type";break;
}

qDebug()<<"\t"<<Q_FUNC_INFO<<":\n\t\t" << 
"WebUrlRequestInterceptor::interceptRequest    " <<info.requestMethod()
   <<"\r\n  "<<info.requestUrl()<<"   "<<rsrct      <<"\r\n";
}


  /*************mainwindow.cpp***************/
 const QUrl url("http://google.com");
 view = new WebView();
 view = new QWebEngineView();
 interceptor = new RequestInterceptor(view);
 profile = new QWebEngineProfile(view);
 profile->setRequestInterceptor(interceptor);
 page = new QWebEnginePage(profile,view);
 view->setPage(page);

Answer 1

经过数小时的搜索，我发现目前无法通过QWebEngine获取HTTP状态代码。加载完成事件也不会返回任何状态代码

然后我找到了解决方法

setting = webpage.settings()
setting.setAttribute(QWebEngineSettings.ErrorPageEnabled, False)

如何从Qt QWebEngineView获取HTTP状态代码？

1 个答案: