Question

我正在尝试编写代码以生成一系列响应：如果用户输入1个数字，多个数字或一个字符串来生成斐波那契数字列表。代码如下：

def fib (a, b):
    return a + b

number = int(input("Please write how many Fibonacci numbers you wish to have generated: "))

fibonacci_list = []
for n in range(number):
    if n in [0, 1]:
        fibonacci_list += [1]
        print("The first", number, "Fibonacci number is:", fibonacci_list)
    elif:
        fibonacci_list += [fib(fibonacci_list[n-2], fibonacci_list[n-1])]
        print("The first", number, "Fibonacci numbers are:", fibonacci_list)
    else:
        print('Sorry could not recognise the input')

Answer 1

您也应该为elif写一个条件，例如：

elif n in [1,2]:

在您的情况下，我将以这种方式编写代码：

def fib (a, b):
    return a + b

try:
    number = int(input("Please write how many Fibonacci numbers you wish to have generated: "))

    fibonacci_list = []
    for n in range(number):

        if n in [0, 1]:
            fibonacci_list += [1]
            print("The first", number, "Fibonacci number is:", fibonacci_list)
        else:
            fibonacci_list += [fib(fibonacci_list[n-2], fibonacci_list[n-1])]
            print("The first", number, "Fibonacci numbers are:", fibonacci_list)
except:
    print('Sorry could not recognise the input')

Answer 2

缺少精灵的条件。

Answer 3

正如其他人所说，您错过了elif中的条件，但是我强烈建议您在这种情况下使用sets

if n in {0,1}:
    ...
elif n in {1,2}:
   ...

sets比列表具有更好的查找时间。另外，this is what they were meant for。

基本用途包括成员资格测试和消除重复条目。

为什么会收到有关使用Elif语句的SyntaxError：无效语法？

3 个答案: