Question

我正在对Java类进行介绍，并且坚持从事我的实验室工作。

我们正在建立一个继承类。教授为我们提供了Main，Address，PersonName，PhoneNumber和PersonRecord。

我们的任务是创建一个包含客户ID，creditCardType，creditCardNumber和creditCardDate的类CustomerRecord。我们指示我们制作一个类，并对“ CustomerRecord而不是Main”进行必要的更改

我继续为该课程设置了所有内容，但继续遇到以下相同错误：

Error:(20, 20) java: constructor CustomerRecord in class edu.cscc.CustomerRecord cannot be applied to given types;
required: java.lang.String,java.lang.String,java.lang.String,java.lang.String
found: edu.cscc.PersonName,edu.cscc.Address,edu.cscc.PhoneNumber,edu.cscc.PhoneNumber,edu.cscc.PhoneNumber,java.lang.String,java.lang.String,java.lang.String,java.lang.String
reason: actual and formal argument lists differ in length

下面是主要部分：

public class Main {

    public static void main(String[] args) {

        // Initialize test data
        Address address = new Address("120 North Tulip Tree Drive",
                "Jackson", "OH", "45640");
        PersonName name = new PersonName("Dr.", "Adelaide", "Penelope",
                "Aardvark", null);
        PhoneNumber homephone = new PhoneNumber(740, 555, 1005);
        PhoneNumber workphone = new PhoneNumber(740, 555, 2356);
        PhoneNumber cellphone = new PhoneNumber(614, 555, 9723);

        // TODO - after creating CustomerRecord class, uncomment the following code.

        // Create sample customer record
        CustomerRecord customer;
        customer = new CustomerRecord (name, address, homephone, workphone, cellphone,
            "123456","Visa","4111-1111-1111-1111", "12/25");

        // Print customer record report
        String namerpt = "Name: " + customer.getName().toString();

        String addressrpt = "Address: " + address.getStreetAddress() + "\n" +
                "\t" + address.getCity() + ", " + address.getState() + " " + address.getZip();

        String phonerpt = "Home Phone: " + customer.getHomePhone().toString() + "\n" +
                "Work Phone: " + customer.getWorkPhone().toString() + "\n" +
                "Mobile Phone: " + customer.getCellPhone().toString();

        System.out.println(namerpt+"\n"+addressrpt+"\n"+phonerpt+"\n"+
                "Customer ID: "+customer.getCustomerID() + "\n"+
                "Credit card type: "+customer.getCreditCardType() + "\n"+
                "Credit card number: "+customer.getCreditCardNumber() + "\n"+
                "Credit card date: "+customer.getCreditCardDate());


    }
}

下面是我创建的Customer类：

public class CustomerRecord {
    private String customerID;
    private String creditCardType;
    private String creditCardNumber;
    private String creditCardDate;





    public CustomerRecord(String customerID, String creditCardType, String creditCardNumber, String creditCardDate) {
        this.customerID = customerID;
        this.creditCardType = creditCardType;
        this.creditCardNumber = creditCardNumber;
        this.creditCardDate = creditCardDate;
    }
    //Accesor//Mutator

    public String getCustomerID() {
        return customerID;
    }

    public void setCustomerID(String customerID) {
        this.customerID = customerID;
    }

    public String getCreditCardType() {
        return creditCardType;
    }

    public void setCreditCardType(String creditCardType) {
        this.creditCardType = creditCardType;
    }

    public String getCreditCardNumber() {
        return creditCardNumber;
    }

    public void setCreditCardNumber(String creditCardNumber) {
        this.creditCardNumber = creditCardNumber;
    }

    public String getCreditCardDate() {
        return creditCardDate;
    }

    public void setCreditCardDate(String creditCardDate) {
        this.creditCardDate = creditCardDate;
    }


}

Answer 1

由于您不应该更改{ ... "parent": "http://localhost:8080/categories/{id}", ... }类，因此请在Main类中添加必要的字段并编辑构造函数，如下所示：

CustomerRecord

这样，private PersonName name; private Address address; private PhoneNumber homephone; private PhoneNumber workphone; private PhoneNumber cellphone; private String customerID; private String creditCardType; private String creditCardNumber; private String creditCardDate; public CustomerRecord(PersonName name, Address address, PhoneNumber homephone, PhoneNumber workphone, PhoneNumber cellphone, String customerID, String creditCardType, String creditCardNumber, String creditCardDate) { this.name = name; this.address = address; this.homephone = homephone; this.workphone = workphone; this.cellphone = cellphone; this.customerID = customerID; this.creditCardType = creditCardType; this.creditCardNumber = creditCardNumber; this.creditCardDate = creditCardDate; }构造函数的所有参数都得到处理。

Answer 2

您有一个仅包含String个参数的构造函数：

public CustomerRecord(String customerID, String creditCardType, String creditCardNumber, String creditCardDate) {

您必须构造一个带有9个参数的构造函数：

前五个是PersonName，Address，PhoneNumber，PhoneNumber和PhoneNumber

接下来的4个是您的String参数

由于您的Main方法具有：

CustomerRecord customer;
    customer = new CustomerRecord(name, address, homephone, workphone, cellphone,
            "123456", "Visa", "4111-1111-1111-1111", "12/25");

Main不会从适当的类中提取信息。继续产生错误

2 个答案: