Question

我的代码如下：

import pytest
import requests
from unittest import mock

@mock.patch('requests.get')
def test_verify(mock_request):
    mock_resp = mock.Mock()
    mock_resp.status_code = 404

    mock_request.return_value = mock_resp
    r = requests.get()

    with pytest.raises(requests.exceptions.HTTPError) as err_msg:
        r.raise_for_status()
    print(err_msg)

由于响应的状态码设置为404，所以我希望会引发HTTPError。但是，显示错误

Failed: DID NOT RAISE <class 'requests.exceptions.HTTPError'>

输出如下：

=========================================测试会话开始==== ==================================平台darwin-Python 3.6.4，pytest-3.7.0 ，py-1.5.2，pluggy-0.7.1 rootdir：/ Users / michael / Code / youtube-data-api，inifile：插件：   requests-mock-1.5.2收集了1个项目

temp_test.py F
  [100％]

============================================失败= =============================================   ____________________________________________ test_verify ____________________________________________

mock_request =
@mock.patch('requests.get')
def test_verify(mock_request):
    mock_resp = mock.Mock()
    mock_resp.status_code = 404

    mock_request.return_value = mock_resp
    r = requests.get()
    #print(r.status_code)

    with pytest.raises(requests.exceptions.HTTPError) as err_msg:
       r.raise_for_status() E           Failed: DID NOT RAISE <class 'requests.exceptions.HTTPError'>
temp_test.py:15：失败 ===================================== 1在0.12秒内失败======== =============================

terminal output

Answer 1

mock_resp是mock.Mock()对象。调用raise_for_status()只会返回另一个Mock()。

您需要使用保留原始raise_for_status()的响应。试试这个：

import pytest
import requests
from unittest import mock

@mock.patch('requests.get')
def test_verify(mock_request):
    mock_resp = requests.models.Response()
    mock_resp.status_code = 404
    mock_request.return_value = mock_resp
    res = requests.get()
    with pytest.raises(requests.exceptions.HTTPError) as err_msg:
        res.raise_for_status()
    print(err_msg)

pytest不使用mock.patch引发HTTPError

1 个答案: