Question

我是python的新手。我拼凑了一个非常有用的代码，除了当我在find_str变量的字符串中有方括号时。我尝试使用双括号，但这也不起作用。

目标是将包含_(FAIL)_的CSV列表中的所有文本替换为SUCCESS。

这是我的代码：

import glob
import re


filenames = sorted(glob.glob('*.csv'))
filenames = filenames
for f2 in filenames:

    csv_name=f2

    # open your csv and read as a text string
    with open(csv_name, 'r') as f:
        my_csv_text = f.read()

    find_str = "_(FAIL)_"
    replace_str = "SUCCESS"


    # substitute
    new_csv_str = re.sub(find_str, replace_str, my_csv_text)


    # open new file and save
    new_csv_path = csv_name 
    with open(new_csv_path, 'w') as f:
        f.write(new_csv_str)

Answer 1

无需使用正则表达式和re.sub()，str.replace()可以完成工作：

find_str = "_(FAIL)_"
replace_str = "SUCCESS"

my_csv_text = 'We go through life and _(FAIL)_ and _(FAIL)_ and _(FAIL)_'

new_csv_str = my_csv_text.replace(find_str, replace_str)

print(new_csv_str)

礼物：

We go through life and SUCCESS and SUCCESS and SUCCESS

Answer 2

看起来您需要逃脱括号

尝试：

find_str = "_\(FAIL\)_"
replace_str = "SUCCESS"

# substitute
new_csv_str = re.sub(find_str, replace_str, my_csv_text)

在使用带括号的字符串时需要帮助

2 个答案: