如何解析作为Multipart FormData发送的服务器端Java代码JSON字符串

Question

我正在REST调用中发送文件和一个javascript对象。即时通讯按如下方式进行：

TypeScript Code :

      formdata.append('file1', this.filedata);
      formdata.append('ctcDetail', JSON.stringify(this.ctcDetailTo));
      this.service.submitFuel(formdata).subscribe(
        info => {
        },
        error => this.errorMessage = error);

    service.ts : 

    submitFuel(formdata){
    return this.http.post(this.url("url"), formdata, new RequestOptions())
      .map((res) => res.json().data.list);

由于formdata仅接受String / blob和File类型，因此我将JS对象转换为String。 现在我将文件检索为byteArray，并且希望将json对象转换为NewCTCDetailTO的实际对象

REST :

@POST
    @Path("/url")
    @Produces(MediaType.APPLICATION_JSON)
    @Consumes(MediaType.MULTIPART_FORM_DATA)
    public RestResponse<?> submitFuel(MultipartFormDataInput input) throws IOException{

        NewCTCDetailTO ctcDetailTO = null;

        if (null == input) {
            return RestResponse.build().sessionTimeout();
        }
        Map<String, List<InputPart>> multipartForm = input.getFormDataMap();
        List<InputPart> inputParts = multipartForm.get("file1");

        InputPart documentPart = inputParts.get(0);
        MultivaluedMap<String, String> header = documentPart.getHeaders();

        InputStream inputStream = documentPart.getBody(InputStream.class, null);
        byte[] bytes = IOUtils.toByteArray(inputStream);

        List<InputPart> inputParts1 = multipartForm.get("ctcDetail");
        InputPart documentPart1 = inputParts1.get(0);

我在Java代码中可以做什么？