我正在使用Google的Books API根据ISBN号获取有关图书的信息。我正在获取缩略图以及其他信息。响应如下所示:
"imageLinks": {
"smallThumbnail": "http://books.google.com/books/content?id=tEDhAAAAMAAJ&printsec=frontcover&img=1&zoom=5&source=gbs_api",
"thumbnail": "http://books.google.com/books/content?id=tEDhAAAAMAAJ&printsec=frontcover&img=1&zoom=1&source=gbs_api"
},
我想在上面的链接上下载缩略图,并将其存储在本地文件系统中。 python怎么办?
答案 0 :(得分:1)
使用urllib
模块
例如:
import urllib
d = {"imageLinks": {
"smallThumbnail": "http://books.google.com/books/content?id=tEDhAAAAMAAJ&printsec=frontcover&img=1&zoom=5&source=gbs_api",
"thumbnail": "http://books.google.com/books/content?id=tEDhAAAAMAAJ&printsec=frontcover&img=1&zoom=1&source=gbs_api"
}
}
urllib.urlretrieve(d["imageLinks"]["thumbnail"], "MyThumbNail.jpg")
Python3X
from urllib import request
with open("MyThumbNail.jpg", "wb") as infile:
infile.write(request.urlopen(d["imageLinks"]["thumbnail"]).read())
答案 1 :(得分:0)
将HTTP请求发送到相应的URL,然后获取content
。然后将内容写入文件。
查看示例
imageLinks = {
"smallThumbnail": "http://books.google.com/books/content?id=tEDhAAAAMAAJ&printsec=frontcover&img=1&zoom=5&source=gbs_api",
"thumbnail": "http://books.google.com/books/content?id=tEDhAAAAMAAJ&printsec=frontcover&img=1&zoom=1&source=gbs_api"
}
import requests
img = requests.get(imageLinks['thumbnail']).content
with open("myfile.jpg", 'wb') as img_file:
img_file.write(img)