使用python将JSON值插入MySQL表

时间:2018-08-01 11:21:00

标签: python mysql json python-requests

我有一个 requests.get

恢复的JSON文件

这是我的一些JSON:

 [{"order":{"id":"B4589B26","status_order_id":5,"status_order_name":"Sent","customer_id":326
"order_products":[{"order_product":{"id":96218,"order_id":96538,"product_id":59320,}}],"customer_email":"user@gmail.com","customer_company":"SARL","customer_name":"user user", .....

这是我的代码:

token = "xxxx"

r = requests.get('url', auth=('user@gmail.com', token))

mydb = pymysql.connect(host='localhost',
user='root',
passwd='user',
db='ytm_db')

cursor = mydb.cursor()

data = r.json()
json_obj = json.loads(r)

for ord in json_obj["order"]:
    print("id:", ord["id"])
    print("status_id:", ord["status_order_id"])
    print('---')
    cursor.execute("INSERT INTO table_test (id, status_order_id, customer_id) VALUES (%s,%s,%s)", (ord["id"], ord["status_order_id"], ord["customer_id"]))

#close the connection to the database.
mydb.commit()
cursor.close()
print ("Done")

我有此错误:

    'not {!r}'.format(s.__class__.__name__))
TypeError: the JSON object must be str, bytes or bytearray, not 'Response'

2 个答案:

答案 0 :(得分:0)

您不需要此行json_obj = json.loads(r)r.json()返回一个json响应。

例如:

json_obj = r.json()

for ord in json_obj["order"]:
    print("id:", ord["id"])
    print("status_id:", ord["status_order_id"])
    print('---')
    cursor.execute("INSERT INTO table_test (id, status_order_id, customer_id) VALUES (%s,%s,%s)", (ord["id"], ord["status_order_id"], ord["customer_id"]))

#close the connection to the database.
mydb.commit()
cursor.close()

答案 1 :(得分:0)

这是正确的解决方案:

json_obj = r.json()

for ord in json_obj:
    print("id:", ord["order"]["id"])
    print("status_id:", ord["order"]["status_order_id"])
    print('---')
    cursor.execute("INSERT INTO table_test (id, status_order_id, customer_id) VALUES (%s,%s,%s)", (ord["order"]["id"], ord["order"]["status_order_id"], ord["order"]["customer_id"]))

#close the connection to the database.
mydb.commit()
cursor.close()