Question

尝试计算重复项形成一个并集所有查询。如果我添加一个组，则消除重复项。我需要计算两个帐户中的两个重复项，但是该帐户中可能有重复项，即时消息无关。因此与众不同

Select CRID.CId as CIds FROM
(
    Select Distinct([CId]) as CId From [dbo].[MyTable] Where AccountId = 'E7888A78-043F-4C34-BB72-1EDC97D32EDB'
    UNION ALL
    Select Distinct([CId]) as CId From [dbo].[MyTable] Where AccountId = 'CC94E667-7776-4427-A6D9-6492C5CDA617'
) CRID
Having Count(CRID.CId > 1) -- Can't use having

Answer 1

因为只有两个表，所以可以这样做：

select count(*) - count(distinct cid) as num_duplicates
from ((Select Distinct([CId]) as CId 
       from [dbo].[MyTable]
       Where AccountId = 'E7888A78-043F-4C34-BB72-1EDC97D32EDB'
      ) union all
      (Select Distinct([CId]) as CId
       from [dbo].[MyTable]
       Where AccountId = 'CC94E667-7776-4427-A6D9-6492C5CDA617'
      )
     ) CRID;

但是，您似乎想要同时具有Cid的{{1}}个。我只想去找

AccountId

如果要计数，请使用子查询：

select cid
from dbo.MyTable
where AccountId in ('E7888A78-043F-4C34-BB72-1EDC97D32EDB', 'CC94E667-7776-4427-A6D9-6492C5CDA617')
group by cid
having count(distinct AccountId) > 1;

计算来自联合所有查询的重复项

1 个答案: