我想解析一个.tsv文件，这不是问题。 问题在于它具有非唯一的标头-就像下面的示例一样，我希望它重新格式化为.json文件。
输入格式（tsv）：
time / s O2 @ Pos. 1 (1/1) sign. ratio warning time / s O2 @ Pos. 2 (2/1) sign. ratio warning time / s O2 @ Pos. 3 (3/1) sign. ratio warning time / s O2 @ Pos. 4 (4/1) sign. ratio warning time / s O2 @ Pos. 5 (5/1) sign. ratio warning time / s O2 @ Pos. 6 (6/1) sign. ratio warning time / s O2 @ Pos. 7 (7/1) sign. ratio warning time / s O2 @ Pos. 8 (8/1) sign. ratio warning time / s O2 @ Pos. 9 (9/1) sign. ratio warning time / s O2 @ Pos. 10 (10/1) sign. ratio warning time / s O2 @ Pos. 11 (11/1) sign. ratio warning time / s O2 @ Pos. 12 (12/1) sign. ratio warning
37 7,6 10,4:1 75 5,1 11,1:1 114 9,0 7,9:1 153 16,5 9,1:1 191 12,6 10,5:1 229 27,4 13,2:1 267 85,8 12,9:1 313 10,0 10,5:1 351 83,5 8,4:1 390 -100,0 0,0:1 Sig.:background and intensity low! 428 34,6 11,1:1 467 89,6 12,4:1
521 9,1 10,0:1 560 8,3 10,9:1 601 8,9 9,2:1 641 16,0 9,6:1 682 12,8 10,8:1 720 27,4 13,3:1 760 85,8 13,1:1 807 9,3 10,9:1 846 79,5 9,0:1 887 13,0 9,1:1 926 36,5 11,1:1 965 87,6 12,7:1
因此有12个重复的四元组：
time / s O2 @ Pos. 1 (1/1) sign. ratio warning
输出格式（json）：
请注意，只有前三个四元组可以使其简短
{
"0 row": {
"0 quadrupel": {
"time / s": "37",
"O2 @ Pos. 1 (1/1)": "7,6",
"sign. ratio": "10,4:1",
"warning": ""
},
"1 quadrupel": {
"time / s": "75",
"O2 @ Pos. 2 (2/1)": "5,1",
"sign. ratio": "11,1:1",
"warning": ""
},
"2 quadrupel": {
"time / s": "114",
"O2 @ Pos. 3 (3/1)": "9,0",
"sign. ratio": "7,9:1",
"warning": ""
},
and so on for the next quadrupel
},
"1 row": {
"0 quadrupel": {
"time / s": "521",
"O2 @ Pos. 1 (1/1)": "9,1",
"sign. ratio": "10,0:1",
"warning": ""
},
"1 quadrupel": {
"time / s": "560",
"O2 @ Pos. 2 (2/1)": "8,3",
"sign. ratio": "10,9:1",
"warning": ""
},
"2 quadrupel": {
"time / s": "601",
"O2 @ Pos. 3 (3/1)": "8,9",
"sign. ratio": "9,2:1",
"warning": ""
}
and so on for the next quadrupel
}
}
我需要一个能解决上述问题的鲁棒算法。 Quadrupel的计数不是固定的，在上面的示例中为12。但是结构始终相同。
非常感谢-任何帮助我都很高兴
matthias