Question

我想编写一个有条件的几列的SQL查询。桌子看起来像这样：

ID          Company           User
1           Bov               LPF
2           Ak                LPF
3           Bov               LPF
4           Bov               ABC
5           Ak                ABC
6           ZP                ABC
7           REP               ABC
8           REP               CDE
9           KEK               CDE
10          Ak                CDE
11          PER               CDE
12          Bov               BKE

结果必须如下：

给每个用户三行（结果中只有至少三行的用户）。
Bov，REP和Ak公司必须至少返回两次结果
这是用于审核的，因此所有内容都必须随机排序（例如，按newid（）排序）
总行为9。

例如预期结果：

ID          Company          User
 1           Bov               LPF
 2           Ak                LPF
 3           Bov               LPF
 4           Bov               ABC
 5           Ak                ABC  
 7           REP               ABC
 8           REP               CDE
 10          Ak                CDE
 11          PER               CDE

我应该如何编写查询？

更新：

我正在考虑这样的查询，但这并不能给我正确的结果：

 select *
  from
  (
  select *,row_number() over(partition by user,company order by user, company) as row, ROW_NUMBER() over(order by newid()) as total
  from
  (
  select *
  from
  (
  select *, 0  as Bov, sum(iif(Company= 'Ak',1,0)) over (order by newid()) as Ak
  FROM table a 
  where Company = 'Ak'
  ) as eu
  where eu.Ak <= 2
  UNION ALL
  select *
  from
  (
    select *, sum(iif(company = 'Bov',1,0)) over (order by newid() )  as Bov, 0 as Ak
  FROM table a
  where Company = 'Bov'
  ) as nn
  where nn.Bov <= 2
  UNION ALL
    select *, 0 as Bov, 0 as Ak
  FROM table a
  where Company not in ('Bov','Ak')
  ) as z
  ) as z1
  where z1.row <= 3
  and z1.total <= 9

过滤器<= 2用于必须返回至少两次结果的公司过滤器row <= 3用于每个用户的三行。过滤器total <= 9用于必须为9的总行。

对于此查询，我不确定我是否至少有两行适用于Bov，Ak和REP公司。

Answer 1

 select *
 from table
 group by id
 having count(User) <= 3
 order by id

这是您需要的吗？

Answer 2

您可以使用它。

DECLARE @MyTable TABLE (ID INT, Company VARCHAR(10), [User] VARCHAR(10))

INSERT INTO @MyTable VALUES
(1  , 'Bov', 'LPF'),
(2  , 'Ak ', 'LPF'),
(3  , 'Bov', 'LPF'),
(4  , 'Bov', 'ABC'),
(5  , 'Ak ', 'ABC'),
(6  , 'ZP ', 'ABC'),
(7  , 'REP', 'ABC'),
(8  , 'REP', 'CDE'),
(9  , 'KEK', 'CDE'),
(10 , 'Ak ', 'CDE'),
(11 , 'PER', 'CDE'),
(12 , 'Bov', 'BKE')


SELECT ID, Company, [User] FROM 
    ( SELECT * 
        , ROW_NUMBER() OVER (PARTITION BY [User] ORDER BY (CASE WHEN Company IN ('Bov','REP','Ak') THEN 0 ELSE 1 END) ) RN
        , COUNT(*) OVER (PARTITION BY [User]) CmpCnt
        , COUNT(CASE WHEN Company IN ('Bov','REP','Ak') THEN 1 END) OVER (PARTITION BY [User]) PriCmpCnt
    FROM @MyTable
    ) T
WHERE 
    T.CmpCnt > 2
and T.PriCmpCnt > 1
and T.RN < 4
order by ID

结果：

ID          Company    User
----------- ---------- ----------
1           Bov        LPF
2           Ak         LPF
3           Bov        LPF
4           Bov        ABC
5           Ak         ABC
7           REP        ABC
8           REP        CDE
10          Ak         CDE
11          PER        CDE

Answer 3

这就是我的处理方式；查看注释以获取解释/让我知道您是否需要更多信息以了解任何内容...

SQL Fiddle Demo

;with cte as 
    (
        select Id
        , Company
        , [User]
        , Row_Number() over (partition by [User] order by randomOrder) PerUserRowNum 
        , case 
            when Company in ('BOV','REP', 'AK') then 
                case 
                    when Row_Number() over (partition by Company order by randomOrder) <= 2 then 1
                    else 0
                end
            else 0 
        end  MustInclude
        from (select *, newid() randomOrder from SourceData) x
    )
    select top 9                --total rows is 9
    Id, Company, [User]
    from cte
    where PerUserRowNum <= 3    --show 3 rows per user
    and [User] in ( --only the users with at least three rows will be in the result
        select [User]
        from cte 
        where PerUserRowNum = 3
    )
    order by MustInclude desc, newid() --ensure all the stuff we must include is returned, then make up the rest of the results with whatever

具有查询条件的SQL查询

3 个答案: