我在Android Studio 3.1.3中创建了3个新项目。问题是每次我将setonclick添加到按钮或手动添加应用程序崩溃的任何视图时,这是我创建的程序之一 这是我的主要JAVA文件
public class MainActivity extends AppCompatActivity {
Button btnRun, btnClear;
EditText txtInput, txtOutput;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
txtInput = findViewById(R.id.txtInput);
txtOutput = findViewById(R.id.txtOutput);
btnClear = findViewById(R.id.btnClear);
btnRun = findViewById(R.id.btnRun);
setContentView(R.layout.activity_main);
/*btnRun.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View view) {
Toast.makeText(MainActivity.this, "Working", Toast.LENGTH_SHORT).show();
}
});*/
txtInput.setText("2");
txtOutput.setText("2 x 1 = 2\n" +
"2 x 2 = 4");
这是我的活动。XML
<?xml version="1.0" encoding="utf-8"?>
<android.support.constraint.ConstraintLayout xmlns:android="http://schemas.android.com/apk/res/android"
xmlns:app="http://schemas.android.com/apk/res-auto"
xmlns:tools="http://schemas.android.com/tools"
android:layout_width="match_parent"
android:layout_height="match_parent"
tools:context=".MainActivity">
<EditText
android:id="@+id/txtOutput"
android:layout_width="221dp"
android:layout_height="0dp"
android:layout_marginBottom="18dp"
android:ems="10"
android:inputType="textMultiLine"
app:layout_constraintBottom_toTopOf="@+id/btnClear"
app:layout_constraintEnd_toEndOf="parent"
app:layout_constraintStart_toStartOf="parent"
app:layout_constraintTop_toBottomOf="@+id/txtInput" />
<Button
android:id="@+id/btnClear"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:layout_marginBottom="60dp"
android:layout_marginEnd="29dp"
android:text="@string/clear_button"
app:layout_constraintBottom_toBottomOf="parent"
app:layout_constraintEnd_toStartOf="@+id/btnRun"
app:layout_constraintHorizontal_chainStyle="packed"
app:layout_constraintStart_toStartOf="parent"
app:layout_constraintTop_toBottomOf="@+id/txtOutput" />
<Button
android:id="@+id/btnRun"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:layout_marginEnd="9dp"
android:layout_marginTop="18dp"
android:text="@string/run_button"
app:layout_constraintEnd_toEndOf="parent"
app:layout_constraintStart_toEndOf="@+id/btnClear"
app:layout_constraintTop_toBottomOf="@+id/txtOutput" />
<EditText
android:id="@+id/txtInput"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:layout_marginBottom="27dp"
android:layout_marginTop="16dp"
android:ems="10"
android:inputType="number"
app:layout_constraintBottom_toTopOf="@+id/txtOutput"
app:layout_constraintStart_toStartOf="@+id/txtOutput"
app:layout_constraintTop_toTopOf="parent" />
请帮助我发现问题 但是,如果我对'setOnClick'进行评论或将其删除,则可以运行该程序
答案 0 :(得分:0)
尝试一下
public class MainActivity extends AppCompatActivity {
Button btnRun, btnClear;
EditText txtInput, txtOutput;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main); // here is the change
txtInput = findViewById(R.id.txtInput);
txtOutput = findViewById(R.id.txtOutput);
btnClear = findViewById(R.id.btnClear);
btnRun = findViewById(R.id.btnRun);
/*btnRun.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View view) {
Toast.makeText(MainActivity.this, "Working", Toast.LENGTH_SHORT).show();
}
});*/
txtInput.setText("2");
txtOutput.setText("2 x 1 = 2\n" +
"2 x 2 = 4");
将初始化放在设置视图之前。它将为null,因为您的所有视图都处于活动状态,并且您是在初始化后进行设置的。