Question

我有一个像这样的字符串-

Course_13_Laravel_Batch_15_Day_22

我想获得此输出

C-13-L-B-15-D-22

我该怎么做？这是我的代码-

<?php
$string = "Course_13_Laravel_Batch_15_Day_22";
$dim = explode(" ", $string);
$str = "";
foreach($dim as $item){
    if(is_numeric( $item)){
        $str = $str."-".substr($item, 0, 2);
    }else{

        $str = $str."-".substr($item, 0, 1);
    }
}
$str = substr($str,1);
echo $str;
?>

Answer 1

当评论进入时，我只是在做正则表达式...

$string = "Course_13_Laravel_Batch_15_Day_22";
echo preg_replace(array('/([a-zA-Z]).*?_/', '/([0-9]+)_/'), '$1-', $string);

输出：

C-13-L-B-15-D-22

Answer 2

$string='Course_13_Laravel_Batch_15_Day_22';

$data=explode('_',$string); // since there is underscore to differ every work/number i use it as my delimiter

foreach($data as $row){
    if(is_numeric($row)){ //check if my array field value is a number
    $newArray[] = $row;
}
else{
        $newArray[]=  $row[0]; //You can access  single characters in a string by using "square brackets"
    }
}


$data=implode('-',$newArray); // merge array fields to a string using implode function and dash delimiter 
  echo $data;

输出为：

C-13-L-B-15-D-22

您可以访问字符串中的单个字符通过使用“方括号”

如何在php中爆炸一个字符串？

2 个答案: