Question

我想对字母数字值进行排序，就像我的输入是

[a1, b1, c1, aa1, bb1, cc1, d1, e1]

输出应按此顺序-a1,b1,c1,d1,e1,aa1,bb1,cc1

我已经使用了这段代码

public class coll {

    public static int comparator(String s1, String s2) {

        String[] pt1 = s1.split("((?<=[a-z])(?=[0-9]))|((?<=[0-9])(?=[a-z]))"); 
        String[] pt2 = s2.split("((?<=[a-z])(?=[0-9]))|((?<=[0-9])(?=[a-z]))"); 
//pt1 and pt2 arrays will have the string split in alphabets and numbers

        int i=0;
        if(Arrays.equals(pt1, pt2))
            return 0;
        else{
            for(i=0;i<Math.min(pt1.length, pt2.length);i++)
                if(!pt1[i].equals(pt2[i])) {
                    if(!isNumber(pt1[i],pt2[i])) {
                        if(pt1[i].compareTo(pt2[i])>0)
                            return 1;
                        else
                            return -1;
                    }
                    else {
                        int nu1 = Integer.parseInt(pt1[i]);
                        int nu2 = Integer.parseInt(pt2[i]);
                        if(nu1>nu2)
                            return 1;
                        else
                            return -1;
                    }
                }
        }

        if(pt1.length>i)
            return 1;
        else
            return -1;
    }

    private static Boolean isNumber(String n1, String n2) {
          // TODO Auto-generated method stub
        try {
            int nu1 = Integer.parseInt(n1);
            int nu2 = Integer.parseInt(n2);
            return true;
        }
        catch(Exception x) {
            return false;
        }

    }

    public static void main(String[] args) {
        // TODO Auto-generated method stub

        String[] examples = {"a1", "b1", "c1", "aa1", "bb1", "cc1", "d1", "e1"};
        List<String> values = new ArrayList<String>(Arrays.asList(examples));

        System.out.println(values);
        Comparator<String> com = (o1,o2) -> {return comparator(o1,o2);}; //lambda expression

        Collections.sort(values,com);
        System.out.println(values);
    }
}

输出为[a1, aa1, b1, bb1, c1, cc1, d1, e1]

但是，我想要

[a1,b1,c1,d1,e1,aa1,bb1,cc1]

Answer 1

从外观上看，这就是您想要的：

public static void main(String[] args) {
    List<String> a = new ArrayList<>(Arrays.asList("a1", "b1", "c1", "aa1", "bb1", "cc1", "aaa1", "d1", "e1"));
    a.sort(Comparator.nullsFirst(Comparator.comparing(String::length).thenComparing(Comparator.naturalOrder())));
    System.out.println(a);
}

您首先按长度排序，然后按长度组对字符串进行排序。

输出为： [a1, b1, c1, d1, e1, aa1, bb1, cc1, aaa1]

Java 7版本：

Collections.sort(a, new Comparator<String>() {
    @Override
    public int compare(String o1, String o2) {
        if (o1 == null) return -1;
        else if (o2 == null) return 1;
        int cmp = Integer.compare(o1.length(), o2.length());
        if (cmp != 0) return cmp;
        return o1.compareTo(o2);
    }
});

以上两个代码示例都是null安全的。

Answer 2

您也可以先onPageSelected()然后再public class MainActivity { private ViewPager mCardsPager; private ViewPager mIpsPager; private MyCreditCardsPagerAdapter mCardsAdapter; private MyInstantPaiementPagerAdapter mIpsAdapter; private List<PayMethod> mCards; private List<PayMethod> mIps; //fill Pager/Adapter/List @Override public void onPageSelected(int position) { if () {//If the page comes from mCardsPager //do Something with mCards } else { //else the page comes from mIpsPager //do Something with mIps } } }

这样做

String::length

输出

String::compareToIgnoreCase

Java中字母数字的排序

2 个答案: