Question

我想获得两次之间的时差，以毫秒为单位。

注意

如果差异超过半秒，它们将返回1000毫秒，那么如何获得适当的毫秒，例如相差半秒就可以得到500毫秒

两次之间的差值为半秒，然后我的代码返回 1000毫秒表示 1秒，但实际上是 0.5秒，因此如何获得 500 毫秒（如果差异为半秒）

    Date Date1 = sdf.parse(lastTime);
    Date Date2 = sdf.parse(sdf.format(Calendar.getInstance().getTime()));
    long millie = Date2.getTime() - Date1.getTime();

Answer 1

SimpleDateFormat默认不包括毫秒。所以

sdf.format(Calendar.getInstance().getTime());

不输出毫秒，所有内容均四舍五入为秒。

定义这样的自定义日期格式，包括毫秒：

SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss.SSSZ\"");

Answer 2

如果您使用java8，请尝试以下操作：

LocalDateTime startTime = LocalDateTime.of(2018,07,31,12,1);
long diff = ChronoUnit.MILLIS.between(startTime,LocalDateTime.now());

Answer 3

通过调用以下方法可以找到两个日期之间的毫秒，秒，分钟和小时之间的时差，您可以根据需要更改方法。

    public void printDifference(Date startDate) {

        Date endDate=new Date();

        long different = endDate.getTime() - startDate.getTime(); //Different in miliseconds

        System.out.println("startDate : " + startDate);
        System.out.println("endDate : "+ endDate);
        System.out.println("different : " + different);
        int months=0,year=0;
        long secondsInMilli = 1000;
        long minutesInMilli = secondsInMilli * 60;
        long hoursInMilli = minutesInMilli * 60;
        long daysInMilli = hoursInMilli * 24;

        long elapsedDays = different / daysInMilli;
        different = different % daysInMilli;

        long elapsedHours = different / hoursInMilli;
        different = different % hoursInMilli;

        long elapsedMinutes = different / minutesInMilli;
        different = different % minutesInMilli;

        long elapsedSeconds = different / secondsInMilli;

    }

Answer 4

尝试下面的代码：

         Date date = null;
         String value="3 Feb 2018 13:01:41 GMT";
         DateFormat formatter = new SimpleDateFormat("dd MMM yyyy HH:mm:ss z");
         formatter.setTimeZone(TimeZone.getTimeZone("GMT"));
         try {
            date = formatter.parse(value);
         } catch (Exception e) {
            e.printStackTrace();
        }
        // Prints the date in the CET timezone
        System.out.println("ConvertTime from serverformat before settimezone ::" + formatter.format(date));
        // Set the formatter to use a different timezone
        formatter.setTimeZone(TimeZone.getDefault());
        // Prints the date in the IST timezone
        System.out.println("ConvertTime from serverformat after settimezone ::" + formatter.format(date));
        DateFormat df = new SimpleDateFormat("dd/MM/yy HH:mm:ss");
        Date dateobj = new Date();
        System.out.println("Current date and time before settimezone:: " + df.format(dateobj));
        df.setTimeZone(TimeZone.getDefault());
        System.out.println("current format after settimezone ::" + df.format(dateobj));
        int difference = 0;
        int diff_Minutes=0;
        int diff_Seconds=0;
        System.out.println("Default values::" + difference+"   "+diff_Minutes+"   "+diff_Seconds);
        difference = (int) (dateobj.getTime() - date.getTime());
        diff_Minutes = difference / (60 * 1000) % 60;
        diff_Seconds = difference / 1000 % 60;

在这里，我正在从服务器时间转换当前时间。在这里，您必须相差两次。我希望你能理解上面的代码。让我知道是否可以... 谢谢。

我想以毫秒为单位获得两次时间之间的时差

4 个答案: