编写正则表达式以从Webpack配置文件中检索配置

Question

我的webpack.config.js文件具有以下配置：

 module:
    {
        loaders:
        [
            { test: /\.js$/, exclude: /node_modules/, loader: 'babel-loader'},
            { test: /\.json$/, loaders: ['json-loader'] },
            { test: /\.svg$/, loader: 'url?limit=65000&mimetype=image/svg+xml' },
            { test: /\.eot$/, loader: 'url?limit=65000&mimetype=application/vnd.ms-fontobject' },
            { test: /\.png$/, loader: 'url?limit=65000&mimetype=image/png' },
            { test: /\.css$/, loader: "style-loader!css-loader" }
        ]
    }

我需要从管道常规脚本读取装入程序部分。我已经尝试过以下正则表达式，但是它不起作用。有人可以帮我吗？

def findStr = "(?<=loaders:)(\\[)(.*)(\\])"

File file = new File('C:/Tools/filewrite/webpack.local.config.js')      
def lines = file.readLines();
StringBuilder strBuild = new StringBuilder();

lines.each { String lineS ->
            strBuild.append(lineS)
          }

  def webpackContent = strBuild.toString();



Pattern p = Pattern.compile(findStr);
Matcher m = p.matcher(webpackContent);

while(m.find())
    {
        def str = m.group();
        echo "${str}";
    }

注意：

  

同一程序在Eclipse groovy项目中可以正常运行，但不能   在Jenkins管道脚本中工作。