我想找到SQL中表的总数

Question

请在下面使用的查询中查找

select cm.city_name,

count(case when k.listing_status_uid=1 then 1 end ) as 'Active',   
count(case when k.listing_status_uid=3 then 1 end ) as 'Bad_listing',  
count(case when k.listing_status_uid=4 then 1 end ) as 'proj_scrapped',  
count(case when k.listing_status_uid=5 then 1 end ) as 'proj_on_hold',  
count(case when k.listing_status_uid=6 then 1 end ) as 'sold_out',  
count(case when k.listing_status_uid=7 then 1 end ) as 'others'

from ksl_listing_master k  
join ksl_locality_master lm on lm.locality_uid=k.listing_locality  
join ksl_city_master cm on cm.city_uid=lm.city_uid  
join ksl_listing_status ls on ls.listing_status_uid=k.listing_status_uid  

group by cm.city_name

这给出了类似下面的输出

现在，我想要每列的总和。 城市名称下方应为Sum 我希望在同一查询中分别计算Active，Bad_listing，proj_scrapped，proj_on_hold，sold_out和others的总和。

Answer 1

如果我理解正确，则只需要一个摘要行。您可以使用with rollup：

select . . .
group by cm.city_name with rollup;

Answer 2

您似乎想要：

select cm.city_name,
       sum(k.listing_status_uid = 1) as 'Active',   
       sum(k.listing_status_uid = 3) as 'Bad_listing',  
       sum(k.listing_status_uid = 4) as 'proj_scrapped',  
       . . .
       sum(k.listing_status_uid in (1,3,4)) as 'total'
from ksl_listing_master k join 
     ksl_locality_master lm 
     on lm.locality_uid = k.listing_locality join 
     ksl_city_master cm 
     on cm.city_uid=lm.city_uid join 
     ksl_listing_status ls 
     on ls.listing_status_uid = k.listing_status_uid  
group by cm.city_name;