Question

我正在使用Jmeter v 4.0 r1823414 。根据{{3}}的建议，逐字使用JSR223 PostProcessor：

建议对任何形式的脚本使用Groovy考虑迁移到JSR223后处理器

在使用这种方法之前，我尝试使用BeanShell Sampler将数据简单地写入csv文件。我从this answer页面获取的代码示例。但是，我遇到了错误

Sourced file: inline evaluation of: ``import java.io.FileWriter; import java.util.Arrays; import java.io.Writer; impor . . . '' : Typed variable declaration : Attempt to access property on undefined variable or class name

好吧，由于建议使用 JSR223 Sampler （或PostProcessor，不确定它们之间在功能方面有什么区别），因此我对代码进行了一些修改，使其更加基于Java在 JSR223采样器中使用：

import java.io.FileWriter;
import java.io.IOException;
import java.util.Arrays;
import java.io.Writer;
import java.util.List;

public class Main {

    //Default separator
    private static char SEPARATOR = ',';

    //get path of csv file (creates new one if its not exists)
    private static String csvFile = "C:/TiredOfProgramming/Work/results.csv"; // for example '/User/Downloads/blabla.csv'

    private static String[] params = {"hello", "world", "jmeter"};

    //function write line in csv
    private static void writeLine(FileWriter writer, String[] parameters, char separator) throws IOException
    {
        boolean firstParameter = true;
        StringBuilder stringBuilder = new StringBuilder();
        String parameter = " ";

        for (int i = 0; i < parameters.length; i++)
        {
            //get param
            parameter = parameters[i];
            log.info(parameter);

            //if the first param in the line, separator is not needed
            if (!firstParameter)
            {
                stringBuilder.append(separator);
            }

            //Add param to line
            stringBuilder.append(parameter);

            firstParameter = false;
        }

        //prepare file to next line
        stringBuilder.append("\n");

        //add to file the line
        log.info(stringBuilder.toString());
        writer.append(stringBuilder.toString());
    }

        FileWriter fileWriter = new FileWriter(csvFile, true);
        writeLine(fileWriter, params, SEPARATOR);

        //proper close to file
        fileWriter.flush();
        fileWriter.close();
}

此特定脚本失败，并显示以下消息：

Script8.groovy：15：意外令牌：hello @第15行，第39列。私有静态String [] params = {“ hello”，“ world”，“ jmeter”};

如果我在 IntelliJ IDE 中对此进行了测试，只是将writeLine方法包装到main方法中，则一切正常

package com.tiredofprogramming;

import java.io.FileWriter;
import java.io.IOException;
import java.util.Arrays;
import java.io.Writer;
import java.util.List;

public class Main {

    //Default separator
    private static char SEPARATOR = ',';

    //get path of csv file (creates new one if its not exists)
    private static String csvFile = "C:\\TiredOfProgramming\\Work\\results.csv"; // for example '/User/Downloads/blabla.csv'

    private static String[] params = {"hello", "world", "jmeter"};

    public static void main(String[] args) throws IOException {
        FileWriter fileWriter = new FileWriter(csvFile, true);
        writeLine(fileWriter, params, SEPARATOR);
        //proper close to file
        fileWriter.flush();
        fileWriter.close();
    }


    //function write line in csv
    private static void writeLine(FileWriter writer, String[] parameters, char separator) throws IOException
    {
        boolean firstParameter = true;
        StringBuilder stringBuilder = new StringBuilder();
        String parameter = " ";

        for (int i = 0; i < parameters.length; i++)
        {
            //get param
            parameter = parameters[i];
            System.out.println(parameter);

            //if the first param in the line, separator is not needed
            if (!firstParameter)
            {
                stringBuilder.append(separator);
            }

            //Add param to line
            stringBuilder.append(parameter);

            firstParameter = false;
        }

        //prepare file to next line
        stringBuilder.append("\n");

        //add to file the line
        System.out.println(stringBuilder.toString());
        writer.append(stringBuilder.toString());

  }
}

我的问题是：groovy sampler是否理解Java（在一篇SO帖子中，我看到提到Groovy理解99％的Java语法）。有没有人成功使用Jmeter将数据写入csv文件？

Answer 1

尝试一下此修改：

//Default separator
char SEPARATOR = ',';

//get path of csv file (creates new one if its not exists)
String csvFile = "C:\\TiredOfProgramming\\Work\\results.csv"; // for example '/User/Downloads/blabla.csv'

def params = ["hello", "world", "jmeter"];

//function write line in csv
def writeLine(FileWriter writer, List<String> parameters, char separator) throws IOException {
    boolean firstParameter = true;
    StringBuilder stringBuilder = new StringBuilder();
    String parameter = " ";

    for (int i = 0; i < parameters.size(); i++) {
        //get param
        parameter = parameters[i];
        log.info(parameter);

        //if the first param in the line, separator is not needed
        if (!firstParameter) {
            stringBuilder.append(separator);
        }

        //Add param to line
        stringBuilder.append(parameter);

        firstParameter = false;
    }

    //prepare file to next line
    stringBuilder.append("\n");

    //add to file the line
    log.info(stringBuilder.toString());
    writer.append(stringBuilder.toString());
}

FileWriter fileWriter = new FileWriter(csvFile, true);
writeLine(fileWriter, params, SEPARATOR);

//proper close to file
fileWriter.flush();
fileWriter.close();

不过，在Groovy中有更简单的方法可以实现相同目的，请查看：

Answer 2

您可以尝试以下代码。这是一个简单的代码段，但是您可以使用JSR223后处理器从Jmeter成功写入csv文件。

select name, amount,
       max(action) over (partition by name, amount order by date) as action,
       date
from t;

Jmeter JSR223采样器-无法将数据写入CSV文件

2 个答案: